Question

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="@..OfferLetter.xslt"?>
<Doc>
<assembly>
<Heading>Offer Letter</Heading>
</assembly>
<RefNo>Ref No:0007</RefNo>
 <Date></Date>
   <to>To</to>
<name></name>
<city></city>
<dear>
<a>Dear Mr.</a>
<name></name>
</dear>
<p1>
  <a1>
  With reference to your application and the subsequent personal interview attended by you,
  we are pleased to inform that you have been selected for employment in ..
  (hereinafter referred to as “Company”).
  We are delighted to make you the following offer for employment.
  </a1>
</p1>
</Doc>

这是我的xslt代码..

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">

<xsl:template match="/">
<html>
  <body>
    <h2 style ="text-align: center;">Offer Letter</h2>
    <h3 style="text-align:Right; margin-right: 110px;">Ref No:K070813</h3>
    <h3 style="text-align:Right ; margin-right: 224px; ">Date:</h3>
    <h3 style="text-align:Left; margin-left: 50px;">To</h3>
    <h3 style="text-align:Left; margin-left: 50px;">MR.</h3>
    <h3 style="text-align:Left; margin-left: 50px;">Hyderabad</h3>
    <br></br>
    <h3 style="text-align:Left; margin-left: 50px;">Dear Mr.</h3>

    <xsl:for-each select="Doc/p1">
      <h3 style="text-align:Left; margin-left: 50px;">
        <xsl:value-of select="a1"/>
      </h3>
    </xsl:for-each>
  </body>
</html>

这里是我的TransformHRML（）代码

public static void TransformXML()
{
    // Create a resolver with default credentials.

    XmlUrlResolver resolver = new XmlUrlResolver();
    resolver.Credentials = System.Net.CredentialCache.DefaultCredentials;

    // transform the OfferLetter.xml file to HTML
    XslTransform transform = new XslTransform();

    // load up the stylesheetfile:

    transform.Load(HttpContext.Current.Server.MapPath("OfferLetter.xslt"));

    // perform the transformation
    transform.Transform(@"..\OfferLetter.xml", @"..\OfferLetter.html", resolver);

    // transform the OfferLetter.xml file to comma delimited format
    // load up the stylesheet

    transform.Transform(HttpContext.Current.Server.MapPath("OfferLetter.xslt"), @"..\OfferLetter.html",resolver);
}

请帮帮我..

Answer 1

有许多关键标记问题，以及Tim提取的@文件中无关的xml。

整理完这些内容后，xslt可以正常使用，但我会推动您使用apply-templates而不是for-each：

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="OfferLetter.xslt"?>
<Doc>
   <assembly>
      <Heading>Offer Letter</Heading>
   </assembly>
   <RefNo>Ref No:0007</RefNo>
   <!--etc-->
   <p1>
      <a1>
         With reference to your application and the subsequent , ...
      </a1>
   </p1>
   <p1>
      <a1>
         Another Paragraph
      </a1>
   </p1>
</Doc>

使用XSLT：

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">

   <xsl:template match="/">
      <html>
         <body>
            <!--Did you mean to hard code these fields? -->
            <h2 style ="text-align: center;">
               <xsl:value-of select="assembly/Heading"/>
            </h2>
            <h3 style="text-align:Right; margin-right: 110px;">
               <xsl:value-of select="assembly/RefNo"/>
            </h3>
            <!--etc-->

            <xsl:apply-templates select="Doc/p1">
            </xsl:apply-templates>
         </body>
      </html>
   </xsl:template>

   <xsl:template match="p1">
      <h3 style="text-align:Left; margin-left: 50px;">
         <xsl:value-of select="a1"/>
      </h3>
   </xsl:template>

</xsl:stylesheet>

xslt没有从xml获取数据？

1 个答案: