我的层次结构是这样的:
我希望能够通过迭代添加上面的层次结构,只要有数据可以从数据库中获取(使用Parse)
我已经尝试将ImageView和LinearLayout放在父LinearLayout下,但它似乎不起作用。这是我在MainActivity.Java中的代码:
LinearLayout LL_Outer = (LinearLayout) findViewById(R.id.new_linearLayoutOuter);
LL_Outer.setOrientation(LinearLayout.VERTICAL); // set orientation
LL_Outer.setBackgroundColor(color.white); // set background
// set Layout_Width and Layout_Height
LinearLayout.LayoutParams layoutForOuter = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.MATCH_PARENT);
LL_Outer.setLayoutParams(layoutForOuter);
LinearLayout LL_Inner = (LinearLayout) findViewById(R.id.new_linearLayoutInner);
LL_Inner.setOrientation(LinearLayout.HORIZONTAL);
LL_Inner.setBackgroundColor(color.white);
LinearLayout.LayoutParams layoutForInner = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
LL_Inner.setLayoutParams(layoutForInner);
//LL_Outer.addView(LL_Inner);
ImageView IV = (ImageView) findViewById(R.id.new_imageViewPP);
//IV.getLayoutParams().height = 55;
//IV.getLayoutParams().width = 55;
LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT);
params.setMargins(14, 12, 0, 0);
params.height = 55;
params.weight = 55;
IV.setBackgroundColor(color.black);
IV.setLayoutParams(params);
LL_Inner.addView(IV);
LL_Outer.addView(LL_Inner);
我不知道哪里出错了,因为我的代码没有提示任何错误。请帮忙。
编辑:我已经相应地编辑了方向,当我运行应用程序时,它停止工作。并在LogCat中提示错误,指出“指定的子节点已经有父节点。您必须首先在子节点的父节点上调用removeView()。
这是我的XML:
<LinearLayout
android:id="@+id/new_linearLayoutOuter"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@color/white"
android:orientation="horizontal" >
<ImageView
android:id="@+id/new_imageViewPP"
android:layout_width="55dp"
android:layout_height="55dp"
android:layout_marginLeft="14dp"
android:layout_marginTop="12dp"
android:background="@color/black"
android:contentDescription="@string/pp" />
<LinearLayout
android:id="@+id/new_linearLayoutInner"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@color/white"
android:orientation="vertical" >
<TextView
android:id="@+id/new_textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/movie_title"
android:paddingTop="10dp"
android:paddingLeft="7dp"
android:textSize="15sp" /> <!-- Title of the movie -->
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/review_by"
android:paddingTop="3dp"
android:paddingLeft="7dp"
android:textSize="12sp" /> <!-- By -->
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/movie_stars"
android:paddingTop="3dp"
android:paddingLeft="7dp"
android:textSize="12sp" /> <!-- Rating and date -->
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/sample_string"
android:maxLines="5"
android:scrollbars="vertical"
android:paddingTop="10dp"
android:paddingLeft="7dp"
android:textSize="12sp"
android:layout_gravity="center_vertical|right" /> <!-- Review content -->
</LinearLayout>
</LinearLayout>
答案 0 :(得分:52)
您希望以编程方式使用该层次结构。
- LinearLayout(horizontal)
- ImageView
- LinearLayout(vertical)
- TextView
- TextView
- TextView
- TextView
好的,让我们从父LinearLayout
LinearLayout parent = new LinearLayout(context);
parent.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
parent.setOrientation(LinearLayout.HORIZONTAL);
//children of parent linearlayout
ImageView iv = new ImageView(context);
LinearLayout layout2 = new LinearLayout(context);
layout2.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
layout2.setOrientation(LinearLayout.VERTICAL);
parent.addView(iv);
parent.addView(layout2);
//children of layout2 LinearLayout
TextView tv1 = new TextView(context);
TextView tv2 = new TextView(context);
TextView tv3 = new TextView(context);
TextView tv4 = new TextView(context);
layout2.addView(tv1);
layout2.addView(tv2);
layout2.addView(tv3);
layout2.addView(tv4);
你完成了:)
答案 1 :(得分:0)
问题是因为视图已添加到XML
文件的布局中。然后你findViewById
(找到它们)并尝试再次将它们添加到布局中。这就是为什么应用程序崩溃抱怨,视图已经有父,你不能再添加它。
答案 2 :(得分:0)
我建议您删除xml文件,而仅在Java端使用完整代码。您可以从Java端以编程方式添加视图。这个来自xtreemdeveloper,但我为父级布局更改了几行。
// remove this params set it up below
parent.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
// change the code above into
.LayoutParams layoutParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,LinearLayout.LayoutParams.MATCH_PARENT);
addContentView(parent,layoutParams);
// end of my change
完整代码=
LinearLayout parent = new LinearLayout(context);
// remove this params set it up below
parent.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
// change the code above into
.LayoutParams layoutParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,LinearLayout.LayoutParams.MATCH_PARENT);
addContentView(parent,layoutParams);
// end of my change
parent.setOrientation(LinearLayout.HORIZONTAL);
//children of parent linearlayout
ImageView iv = new ImageView(context);
LinearLayout layout2 = new LinearLayout(context);
layout2.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
layout2.setOrientation(LinearLayout.VERTICAL);
parent.addView(iv);
parent.addView(layout2);
//children of layout2 LinearLayout
TextView tv1 = new TextView(context);
TextView tv2 = new TextView(context);
TextView tv3 = new TextView(context);
TextView tv4 = new TextView(context);
layout2.addView(tv1);
layout2.addView(tv2);
layout2.addView(tv3);
layout2.addView(tv4);
答案 3 :(得分:-1)
在XML文件中,LinearLayout已经有了子视图。因此不需要在代码中添加它们。