android Lrucache:无法检索缓存的位图

时间:2013-11-29 08:30:07

标签: android bitmap out-of-memory android-lru-cache

我能够将位图插入LruCache,但无法检索以前的解码图像。我的数据库中有超过100张图像。当我解密它时,我的gc记忆正在增加。所以我正在实现这个以重用解码图像。

protected void onCreate()
{
    LruCache<String, Bitmap> mMemoryCache;
    codeforLru_oncreate();
    aa1=getBitmapFromMemCache(String.valueOf(aa));
    if (aa1 != null) 
    {
      iv.setImageBitmap(aa1);
    } 
    else
    {
      aa1= decodeSampledBitmapFromResource(aa);
      addBitmapToMemoryCache(String.valueOf(aa), aa1);
      iv.setImageBitmap(aa1);
    }
}

获取最大可用VM内存,超过此数量将引发OutOfMemory异常。存储为千字节,因为LruCache在其构造函数中使用int

public void codeforLru_oncreate() {

    final int maxMemory = (int) (Runtime.getRuntime().maxMemory() / 1024);
    // Use 1/8th of the available memory for this memory cache.
    final int cacheSize = maxMemory / 64;
    mMemoryCache = new LruCache<String, Bitmap>(cacheSize) {
        @Override
        protected int sizeOf(String key, Bitmap bitmap) {
            // The cache size will be measured in kilobytes rather than
            // number of items.
            //app.setFlagForMemoryAlloc(1);
            return bitmap.getByteCount() / 1024;
        }
    };

}
   // code for adding bitmap into cache memory
  public void addBitmapToMemoryCache(String key, Bitmap bitmap) 
    {
    if (getBitmapFromMemCache(key) == null) {

        mMemoryCache.put(key, bitmap);
    }
}



//code for get bitmap from cache memory
public Bitmap getBitmapFromMemCache(String key) {
    return mMemoryCache.get(key);
}

//decoding here......
public Bitmap decodeSampledBitmapFromResource(byte[] decodethis)
{
     return                BitmapFactory.decodeByteArray(decodethis,0,decodethis.length,option);
}  

0 个答案:

没有答案