我不熟悉从pthread启动程序中返回的东西,所以我来到SO寻求帮助。
启动例程将计算给定范围的一些素数,将它们存储在一个int数组中,然后将该数组返回到将要打印的主数据。
如果有不同的方法来实现这一点,我很乐意听到它!
这就是我所拥有的:
//start routine
void *threadCreate(void* arg){
int threadNumber = threadCount;
threadCount++;
Data *data;
data = (struct Data*)arg;
int primes[data->end]; //I don't know how many primes we will have, but I think if I use the end range value as a size it will be more than enough.
int k = 0; //Index of the int array
printf("Thread #%d results: ", threadNumber);
for (int i = data->start; i <= data->end; i++){
if (isPrime(i)){
printf("%d ", i);
primes[k] = i;
k++;
}
}
printf("\n");
pthread_exit((void*)primes);
}
//in main, this is where we print our array
//I don't know the correct way to get this array
void *retval;
pthread_join(tid, &retval);
//im aware the next part is more than likely incorrect, I am just trying to illustrate what I am trying to do
for (int i = 0; i < len((int [])retval); i++){
printf("%d ", (int[])retval[i]);
}
答案 0 :(得分:3)
您返回的指针不能是线程函数中具有自动存储持续时间的数组,因为一旦线程函数返回它将被销毁。但是,您可以使用动态分配。主函数还需要知道返回数组中有多少个数字 - 最简单的方法是使用零作为标记,因为零的素数是未定义的。
int *primes = malloc((data->end + 1) * sizeof primes[0]);
if (primes)
{
int k = 0; //Index of the int array
for (int i = data->start; i <= data->end; i++)
{
if (isPrime(i))
{
printf("%d ", i);
primes[k] = i;
k++;
}
}
primes[k] = 0; /* Add sentinel to mark the end */
}
pthread_exit(primes);
然后在主要功能中:
void *retval;
int *primes;
pthread_join(tid, &retval);
primes = retval;
if (primes != NULL)
{
for (int i = 0; primes[i] != 0; i++)
{
printf("%d ", primes[i]);
}
}
else
{
/* Thread failed to allocate memory for the result */
}
free(primes);
您也可以在传递给线程函数的Data
结构中为结果分配一个数组,并将其填入其中。