Question

我的CakePHP应用程序有以下查找查询：

$this->paginate = array(
'limit'=>5,
'order'=>'Note.datetime DESC',
'conditions' => array(
    'Note.status'=>1,
    'OR' => array(
        'Note.title LIKE' => '%'. $q . '%',
        'Note.content LIKE' => '%'. $q . '%'
        )
    )
);

使用名为$q的参数来对标题和内容进行查询。

例如，如果我有以下内容：

Title: Lorem ipsum Content: Lorem ipsum dolare

搜索'lorem'

它会很好。但如果我搜索'lorem dolare'，它就找不到它。

我该怎么做？

注意：我不想使用任何插件等。

编辑：如果我使用FULLTEXT，这会有效吗？

$this->paginate = array(
'limit'=>5,
'order'=>'Note.datetime DESC',
'conditions' => array(
    'Note.status'=>1,
    'OR' => array(
        'MATCH(Note.title) AGAINST('.$q.' IN BOOLEAN MODE)',
        'MATCH(Note.content) AGAINST('.$q.' IN BOOLEAN MODE)'
        )
    )
);

编辑2：

尝试以上操作时出现此错误：

 Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'dolor IN BOOLEAN MODE)) OR (MATCH(`Note`.`content`) AGAINST(lorem dolor IN BOOLE' at line 1

SQL Query: SELECT `Note`.`id`, `Note`.`title`, `Note`.`excerpt`, `Note`.`content`, `Note`.`datetime`, `Note`.`user_id`, `Note`.`slug`, `Note`.`status`, `Note`.`topic_id`, `User`.`id`, `User`.`email`, `User`.`firstname`, `User`.`lastname`, `User`.`password`, `User`.`status`, `Topic`.`id`, `Topic`.`title`, `Topic`.`slug` FROM `db52704_driz2013`.`notes` AS `Note` LEFT JOIN `db52704_driz2013`.`users` AS `User` ON (`Note`.`user_id` = `User`.`id`) LEFT JOIN `db52704_driz2013`.`topics` AS `Topic` ON (`Note`.`topic_id` = `Topic`.`id`) WHERE `Note`.`status` = 1 AND ((MATCH(`Note`.`title`) AGAINST(lorem dolor IN BOOLEAN MODE)) OR (MATCH(`Note`.`content`) AGAINST(lorem dolor IN BOOLEAN MODE))) ORDER BY `Note`.`datetime` DESC LIMIT 5

Answer 1

试试这个

$this->paginate = array(
    'limit'=>5,
    'order'=>'Note.datetime DESC',
    'conditions' => array(
        'Note.status'=>1,
        'OR' => array(
            "MATCH(Note.title) AGAINST('".$q."' IN BOOLEAN MODE)",
            "MATCH(Note.content) AGAINST('".$q."' IN BOOLEAN MODE)"
        )
    )
);

换句话说，请用引号

括起搜索条件

编辑ndm的建议有意义

$this->paginate = array(
    'limit'=>5,
    'order'=>'Note.datetime DESC',
    'conditions' => array(
        'Note.status'=>1,
        'OR' => array(
            'MATCH(Note.title) AGAINST(? IN BOOLEAN MODE)' => $q,
            'MATCH(Note.content) AGAINST(? IN BOOLEAN MODE)' => $q
        )
    )
);

Answer 2

你也可以试试这个：

$this->paginate = array(
    'limit'=>5,
    'order'=>'Note.datetime DESC',
    'conditions' => array(
        'Note.status'=>1,
        'OR' => array(
            'Note.title LIKE' => "%$q%",
            'Note.content LIKE' => "%$q%"
        )
    )
);

Answer 3

LIKE在这里不会帮到你。您的标题为Lorem ipsum，内容为Lorem ipsum dolare。您正在搜索lorem dolare，它不会通过LIKE运算符找到，因为它不是这些列中的任何一个子串。您需要考虑使用FULLTEXT，否则您需要使用类似Sphinx的内容。如果您正在尝试找出要实施的解决方案，请查看this answer here。

Answer 4

Please Try this:

$this->paginate = array(
    'limit'=>5,
    'order'=>'Note.datetime DESC',
    'conditions' => array(
        'Note.status'=>1,
        'OR' => array(
            'Note.title LIKE' => "%".$q."%",
            'Note.content LIKE' => "%".$q."%"
        )
    )
);

CakePHP使用％like％查找查询

4 个答案: