Question

我正在尝试将我程序中的一个矩阵与常量相乘，但由于没有现有方法可以做到这一点，我想我必须重载运算符等。但是因为我已经将“*”运算符重载了一次。它还需要从左侧而不是从右侧获取值或更具体的常量。我该怎么办？

感谢所有帮助！

重载*运算符

matrix operator * (matrix const arg){

    double sum = 0;
    int x = 0;
    int rowY = 0;
    int rowX = 0;
    this->matrix_array_multiply = new double[row*arg.col];
    for (int position = 0; position < row*arg.col; position++, x++){

        if (arg.matrix_array[x*arg.row] == (arg.matrix_array[arg.row*arg.col])){

            //If last number in second matrix, reset these values and proceed with next row of Y-values.

            x = 0;
            rowY++;

        }

        for (int y = 0; y < arg.row; y++, rowX++){

            sum = sum + (matrix_array[y + (rowY*col)]) * (arg.matrix_array[x + (rowX*arg.col)]);

        }

        matrix_array_multiply[position] = sum;
        rowX = 0;
        sum = 0;

    }

    matrix new_matrix_multiply(matrix_array_multiply, row, arg.col); //Create new instance of new matrix.
    return new_matrix_multiply; //Return new matrix.

}

使用不同的矩阵和运算符：

int main () {

double a[] =  { 3, 0, 3, 4,
                3, 4, 2, 4,
                5, 3, 2, 1 };

double b[] =  { 6, 3, 5, 7,
                9, 8, 6, 4,
                6, 5, 3, 1 };

double c[] =  { 1, 2, 3, 4,
                5, 6, 7, 8,
                9, 2, 1, 1,};

double d[] =  { 6, 5, 4, 3,
                2, 1, 0, 1,
                2, 3, 4, 5,
                6, 7, 8, 9};

double e[] = { 1, 2, 1,
               3, 5, 7,
               9, 7, 3};

matrix matrix1(a, 3, 4); //Instance of the class matrix: array, rows, columns.
matrix matrix2(b, 3, 4);
matrix matrix3(c, 3, 4);
matrix matrix4(d, 4, 4);
matrix matrix5(e, 3, 3);

matrix matrix6 = (matrix1 + matrix2);
matrix matrix7 = (matrix2 - matrix1);
matrix matrix8 = (matrix3 * matrix4);
matrix matrix9 = ~matrix5;
matrix matrix10 = (5.7 * matrix5); // Error: no operator "*" matches these operands, operand types are: double * matrix 
}

注意：我刚开始学习c ++，这是作业的一部分。

Answer 1

matrix matrix10 = (5.7 * matrix5);

为此，您需要使用此签名定义 free 函数：

matrix operator*(double c, matrix const & m) //non-member function
{
   //your code
}

同样，您也想对此进行定义：

matrix operator*(matrix const & m, double c)
{
    return c * m; //call the other overload!
}

试图将矩阵与常量，重载运算符相乘两次？

1 个答案: