Question

我为从日志文件读取的每个输入行生成了一行列表我想遍历每个列表并解析列表中的日期属性位，请提供您的建议

listgen  = line.split() 

['2013-07-23T14:08:17.111906+01:00', 'server24', 'status=inprogress', 'MSG= Transfer Intitated']
['2013-07-23T14:08:26.630043+01:00', 'server x2', 'status=waiting', 'MSG= waiting for response']
['2013-07-23T14:08:27.188360+01:00', 'server35', 'status=waiting', 'MSG= waiting for response']
['2013-07-23T14:08:27.306438+01:00', 'server35x', 'status=successful', 'MSG= Transfer Completed']
['2013-07-23T14:08:27.342922+01:00', 'serverx56', 'status=inprogress', 'MSG= Transfer Intitated']
['2013-07-23T15:12:10.803993+01:00', 'server267', 'status=waiting', 'MSG= waiting for response']

我想遍历每个列表并解析列表中的日期属性

for i in listgen:
    #print [i:]        
    dat_e = parser.parse(listgen[0])

预期产出：

2013-07-23 14:08:17.111906+01:00
2013-07-23 14:08:26.630043+01:00
2013-07-23 14:08:27.188360+01:00
2013-07-23 14:08:27.306438+01:00
2013-07-23 14:08:27.342922+01:00
2013-07-23 15:12:10.803993+01:00

Answer 1

嗯...

for i in listgen:
    #print [i:]
    print i[0].replace('T', ' ')

Answer 2

for item in listgen:
    date = item[0].replace('T', ' ')
    print date
    #do other things with date

Answer 3

你需要这样做：

假设：

listgen = [['2013-07-23T14:08:17.111906+01:00', 'server24', 'status=inprogress', 'MSG= Transfer Intitated'],['2013-07-23T14:08:26.630043+01:00', 'server x2', 'status=waiting', 'MSG= waiting for response'],['2013-07-23T14:08:27.188360+01:00', 'server35', 'status=waiting', 'MSG= waiting for response'],['2013-07-23T14:08:27.306438+01:00', 'server35x', 'status=successful', 'MSG= Transfer Completed'],['2013-07-23T14:08:27.342922+01:00', 'serverx56', 'status=inprogress', 'MSG= Transfer Intitated'],['2013-07-23T15:12:10.803993+01:00', 'server267', 'status=waiting', 'MSG= waiting for response']]


for i in listgen:
    print i[0] # that's your date part

你可以应用你想要的任何功能（如解析等）。

遍历每个列表

3 个答案: