Question

我有一个ajax函数，它向api发送get请求并以下列格式返回数据 -

{
    "firstname": "John",
    "lastname": "Doe",
    "email": "doej@gmail.com",
    "subjects": [
      {
        "id": 1,
        "name": "maths"
      },
      {
        "id": 2,
        "name": "chemistry"
      }
    ]
  },

我需要在表格中显示这些数据，但是无法正确显示主题数组，即作为一个表格单元格中的列表。我试图将数组数据放入主数据库中的另一个表中，但它没有用完。我认为我在迭代循环中的某个地方出错了。

function getPeople() {


     $.ajax({
         type: "GET",
         url: "http://example.com",
         contentType: "application/json; charset=utf-8",
         crossDomain: true,
         dataType: "json",
         success: function (data, status, jqXHR) {



             // fill a table with the JSON
           $("table.mytable").html("<tr><th></th><th>First Name</th><th>Last Name</th><th>Subjects</th></tr>"  );

for (var i = 0; i < data.length; i++) {

        for (var j = 0; j < data[i].subjects.length; j++) {

          var subjects = data[i].subjects[j];
        $("table.insidetable").append('<tr><td>' + subjects + 'tr><td>')
      }

    $("table.mytable").append('<tr><td><input type = "checkbox" id = '+data[i].id+'>'  + "</td><td>" + data[i].firstname + "</td><td>" + data[i].lastname + "</td><td>" + "table.insidetable"  + "</td></tr>");
}

         },

         error: function (jqXHR, status) {
             // error handler
             console.log(jqXHR);
             alert('fail' + status.code);
         }
      });
   }

Answer 1

以下是工作（测试）代码。

var data = [{
  "firstname": "John",
  "lastname": "Doe",
  "email": "doej@gmail.com",
  "subjects": [
    {
        "id": 1,
    "name": "maths"
    },
    {
        "id": 2,
        "name": "chemistry"
    }
        ]
},
{
  "firstname": "Steve",
  "lastname": "Gentile",
  "email": "steve@gmail.com",
  "subjects": [
    {
    "id": 1,
    "name": "history"
    },
    {
        "id": 2,
    "name": "geography"
    }
  ]
}];

$("table.mytable").html("<tr><th></th><th>First Name</th><th>Last Name</th><th>Subjects</th></tr>");

for (var i = 0; i < data.length; i++) {
    var subjectList = '';

    for (var j = 0; j < data[i].subjects.length; j++) {
      subjectList += '<li>' + data[i].subjects[j].name + '</li>';
    }

    $("table.mytable").append('<tr><td><input type="checkbox" id=' + i +'/></td><td>' + data[i].firstname + '</td><td>' + data[i].lastname + '</td><td><ul>' + subjectList  + '</ul></td></tr>');
}

似乎下面的陈述中有很多问题，如

标签未正确关闭
正在使用不存在的属性（data [i] .id）
单引号和双引号不匹配

...

$("table.mytable").append('<tr><td><input type = "checkbox" id = '+data[i].id+'>'  + "</td><td>" +data[i].firstname + "</td><td>" + data[i].lastname + "</td><td>" + "table.insidetable"+ "</td></tr>");

Answer 2

猜猜你错过了'<'？

在行中：

 $("table.insidetable").append('<tr><td>' + subjects + 'tr><td>')

另外

$("table.mytable").append('<tr><td><input type = "checkbox" id = '+data[i].id+'>'  + "</td><td>" + data[i].firstname + "</td><td>" + data[i].lastname + "</td><td>" + "table.insidetable"  + "</td></tr>");

我认为你不应该追加“table.insidetable”吗？这将被视为值“table.insidetable”，而不是表的内容。我认为这应该是$("table.insidetable").val()

数组数据不会显示在表格中

2 个答案: