Question

我在Contact.php模型中有这两种方法：

public function getSubscribers($listId)
{
    return $this->withTrashed()
        ->where(DB::raw("concat('',email * 1)"), '!=', DB::raw('email'))
        ->where('opt_out', '0')
        ->select('email')
        ->chunk(1000, function($results) use ($listId) { $this->subscribeEmails($listId, $results); });
}

public function subscribeEmails($listId, $subscribers)
{
    $emails = array();

    foreach ($subscribers as $key => $subscriber)
    {
        $memberActivity = $subscriber->memberActivity($listId);

        if ( ! $memberActivity['data'])
        {
            $emails[] = array('email' => $subscriber->email);
        }
        else
        {
            foreach ($memberActivity['data'] as $data)
            {
                foreach ($data['activity'] as $activity)
                {
                    if ($activity['action'] !== 'unsub')
                    {
                        $emails[] = array('email' => $subscriber->email);
                    }
                }
            }  
        }
    }

    MailchimpWrapper::lists()->batchSubscribe($listId, $emails, false, true);
}

通过名为updateMailchimp（）的方法在我的AdminContactsController.php控制器中调用getSubscribers（）方法：

public function updateMailchimp()
{
    $this->contact->getSubscribers($this->listId);

    $message = (object) array(
        'title'         => 'Excellent!',
        'content'       => 'The Mailchimp newsletter list has been updated with the latest contacts from within the system.',
        'alert_type'    => 'success'
    );

    return Redirect::back()->with('message', $message);
}

在本地，这很好，除了在登台服务器上没有任何问题，我得到以下错误引用行cotaining - ＆gt; chunk（1000，function（$ results）use（$ listId）{$ this-＆gt ; subscribeEmails（$ listId，$ results）;}）;：

Using $this when not in object context

这是PHP版本问题还是我在这里遗漏了什么？

Answer 1

您的代码在localhost上工作但在远程服务器上工作的原因可能与PHP版本不同。在PHP 5.4.0之前 it is not possible to use $this from anonymous function 。您必须将$this关键字中的引用传递给use：

public function getSubscribers($listId)
{
    $that = $this; // <---- create reference to $this
    return $this->withTrashed()
        ->where(DB::raw("concat('',email * 1)"), '!=', DB::raw('email'))
        ->where('opt_out', '0')
        ->select('email')
        ->chunk(1000, function($results) use (&$that, $listId) { $this->subscribeEmails($listId, $results); });
}

不在对象上下文中时使用$ this - Laravel 4

1 个答案: