Java HTTP Post表单和文件

Question

所以我想使用TestFairy API（url：https://app.testfairy.com/api/upload）。此API调用需要3个后参数：

• api_key（字符串）

• apk_file（。apk文件）

• testers_groups（字符串）

到目前为止，我提出了这个问题：

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);

List <NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("testers_groups", testers));
params.add(new BasicNameValuePair("api_key", key));

httppost.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));

MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("apk_file", new FileBody(file));

httppost.setEntity(reqEntity);

System.out.println("executing request " + httppost.getRequestLine());
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();

System.out.println(response.getStatusLine());
if (resEntity != null) {
    System.out.println(EntityUtils.toString(resEntity));
}
if (resEntity != null) {
    resEntity.consumeContent();
}

httpclient.getConnectionManager().shutdown();

但它不起作用。

有人能指出我正确的方向吗？

Answer 1

尝试这样的事情：

MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("api_key", new StringBody(key));
entity.addPart("apk_file", new FileBody(file));
entity.addPart("testers_groups", new StringBody(testers));
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(entity);

HttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(httpPost);

可选择在StringBody和FileBody构造函数中添加mime类型（但可能不是必需的）。