Question

如何获得“client_type = 0”的所有“clid”？管道字符“|”分离每个客户信息。我的文字只有一行：

clid = 2 cid = 3346 client_database_id = 5153 client_nickname = xLukas \ s \ p \ sLukas client_type = 0 | clid = 3 cid = 3346 client_database_id = 1 client_nickname = powered \ sby \ sMirWayne.DE client_type = 1 | clid = 4 cid = 3346 client_database_id = 9661 client_nickname = Number \ sone client_type = 0 | clid = 5 cid = 3469 client_database_id = 1 client_nickname = powered \ sby \ sMirWayne client_type = 1 | clid = 6 cid = 1716 client_database_id = 1 client_nickname = FG \ sBot client_type = 1 | clid = 7 cid = 3469 client_database_id = 9661 client_nickname = Number \ stwo client_type = 0 | clid = 8 cid = 1762 client_database_id = 4351 client_nickname = pr0zkillz1x \ pTobi client_type = 0 | clid = 9 cid = 1764 client_database_id = 5160 client_nickname = xL1mited \ s / \ sMax client_type = 0 | clid = 10 cid = 1716 client_database_id = 9704 client_nickname = Sebi client_type = 0 | clid = 13 cid = 3346 client_database_id = 4336 client_nickname = checker284 \ s \ p \ sSebbo client_type = 0 | clid = 19 cid = 1762 client_database_id = 9312 client_nickname = pr0skillz1x \ pDanie client_type = 0 | clid = 30 cid = 3346 client_database_id = 9697 client_nickname = TeamSpeakUser client_type = 0 | clid = 33 cid = 1716 client_database_id = 1 client_nickname = serveradmin client_type = 1

我需要alle clid，它在额外的行中有client_type = 0。例如：

    clid=2
    clid=3
    clid=4
    clid=5
    ...

我目前的解决方案无效：

    cat clientlist.txt | grep -Eo "clid=[0-9]+[\d\D]*client_type=0" | grep -Eo "clid=[0-9]+"

有人可以帮忙吗？

Answer 1

使用sed：

tr '|' '\n' < file | sed -n '/client_type=0/s/\(clid=[0-9]*\).*$/\1/p'
clid=2
clid=4
clid=7
clid=8
clid=9
clid=10
clid=13
clid=19
clid=30

Answer 2

管道字符“|”分离每个客户信息。

利用这些信息，您可以说：

tr '|' '\n' < clientlist.txt | grep -Po 'clid=\d+(?=.*client_type=0)'

对于您的输入，结果是：

clid=2
clid=4
clid=7
clid=8
clid=9
clid=10
clid=13
clid=19
clid=30

Linux shell脚本：如何将子字符串与正则表达式匹配

2 个答案: