PHP Array,通过一系列索引访问数组值

时间:2013-11-28 05:57:30

标签: php arrays indexing range arrayaccess

我的情况是我的物品价格在公斤范围内,比如

price in range 0.01-0.04 is 5
price in range 0.05-0.09 is 30
price in range 0.1-0.15 is 50  

这是我想要的数组样本

$prices = array("0.01-0.04"=>5,"0.05-0.09"=>30);

现在我想创建一个数组,以便在用户输入0.02 it should return price in range 0.01-0.04时为5,类似用户input 0.07 so it should return 30

如何在PHP中创建数组以通过一系列索引访问数组?

4 个答案:

答案 0 :(得分:2)

试用此代码

 <?php
        $price = array(
            array(
                'min_range' => 0.1,
                'max_range' => 0.4,
                'price'     => 5
            ),
            array(
                'min_range' => 0.5,
                'max_range' => 0.9,
                'price'     => 30
            ),
            array(
                'min_range' => 1.0,
                'max_range' => 1.5,
                'price'     => 50
            ),
        );

        $input = 0.7;

        foreach( $price as $p){
            if($input>=$p['min_range'] && $input<=$p['max_range']){
                echo $p['price'];
                break;
            }
        }

    ?>

答案 1 :(得分:2)

将$ no变量设置为您要查找范围的数字

    <?php

$no = 0.05;
$ranges = array
  (
  array(0.01,0.04,5),
  array(0.05,0.09,30),
  array(0.1,0.15,50)
  );
  $foundFlag=false;
 foreach ($ranges as $range) { 

        if($no>=$range[0] && $no<=$range[1])
        {
        $foundFlag=true;
            echo "$range[2]";
        }
} 
  if($foundFlag==false)
  {
    echo "range not found";
  }

?>

答案 2 :(得分:0)

你也可以这样尝试,

  <?php

     $input = $_POST['userInput'];
     $count = 0;

     $arr =Array();
     $arr[0]=0.01;
     $arr[1]=0.04;
     $arr[2]=0.05;
     $arr[3]=0.09;
     $arr[4]=0.1;
     $arr[5]=0.15;

     $price =Array();
     $price[0] =5;
     $price[2] =30;
     $price[4] =50;

     while(count($arr)>$count)
        if($arr[$count] != null && $arr[$count+1] != null)
        {
             if($input >$arr[$count] && $input <$arr[$count+1])
             {
                echo "price is $price[$count]";
             }
        }
        $count = $count +2;
     }
 ?>

答案 3 :(得分:0)