Question

我有一个如下数组：

var someArray = ['val1','val2','val3','val4','val5','val6','val7','val8','val9','val10','val11','val12'];

我正试图找出一些优雅的方法，使用underscore，简单地将其转换为如此数组的数组......

[['val1','val2','val3','val4'], ['val5','val6','val7','val8'], ['val9','val10','val11','val12']]

其中新数组的每个索引都是来自第一个数组的四个元素的组。使用underscore.js是否有一种简单优雅的方式。

Answer 1

下划线，因为您问过：（Example）

var i = 4, list = _.groupBy(someArray, function(a, b){
    return Math.floor(b/i);
});
newArray = _.toArray(list);

Vanilla JS：（Example）

var newArray = [], size = 4;
while (someArray.length > 0) newArray.push(someArray.splice(0, size));

Answer 2

纯JavaScript解决方案，使用splice()：

Object.defineProperty( Array.prototype, 'eachConsecutive', {
  value:function(n){
    var copy = this.concat(), result = [];
    while (copy.length) result.push( copy.splice(0,n) );
    return result;        
  }
});

var someArray = ['val1','val2','val3','val4','val5','val6','val7','val8','val9','val10','val11','val12'];
var chunked = someArray.eachConsecutive(4);
//-> [["val1","val2","val3","val4"],["val5","val6","val7","val8"],["val9","val10","val11","val12"]]

Unflatten阵列成四肢组

2 个答案: