Question

word1 = 'index.php/1'
word2 = 'index.php/2'
try:        
    tentativa1 = urllib2.urlopen(site + word1)
    tentativa2 = urllib2.urlopen(site + word2)

except URLError as e:
    tentativa1 = e
    tentativa2 = e

lista = [tentativa1, tentativa2]
    for website in lista:
     if website.code == 200:
        website = website.read()
        print '\n:)' if 'registration' in website else '\n:/'
        print '\n:)' if 'there is no form' in website else '\n:/'

我没有收到错误但是没有打印它应该是什么。想法是输入一个用两个或多个字符串连接的网站，然后是“.read（）”如果找到“keywords”将打印“:)”。

Answer 1

你可以尝试这段代码并告诉我什么是打印输出

sites = [site + 'index.php/1', site + 'index.php/2']

for url in sites:
    try:
        website = urllib2.urlopen(url)
    except URLError as e:
        print '{}: {}'.format(url, repr(e))
    else:
        if website.code == 200:
            website = website.read().lower()
            print '\n:)' if 'registration' in website else '\n:/'
            print '\n:)' if 'there is no form' in website else '\n:/'        
        else:
            print '{}: code {}'.format(url, website.code)

它不是因为Python中的变量很少而打印的

1 个答案: