Question

我有一个注册部分，其中使用rest服务发送用户名和密码进行解析。这工作正常。在登录部分，我想检查用户名和密码是否在解析中注册，所以我采取了http响应，但我的代码中有一些错误。由于某种原因，回复没有回来。

我的loginSuccesfull方法如下：

private boolean loginSuccesfull() throws ClientProtocolException, IOException {
        // TODO Auto-generated method stub
        InputStream result = null;
        HttpClient httpClient = new DefaultHttpClient();
        HttpGet get = new HttpGet("https://api.parse.com/1/classes/Login?where={"+"\"UserName\""+":"+"\"abc\""+"}"); 
        HttpResponse response = httpClient.execute(get);
        if (response != null && response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
            BufferedHttpEntity bufferedHttpEntity = new BufferedHttpEntity(response.getEntity());
            result = bufferedHttpEntity.getContent();
            return true;
        }else {
            // insert error handling
            return false;
        }       
    }

Answer 1

to make a successful HTTP response and handle all exception , use the following Code:




        HttpParams httpParams = new BasicHttpParams();
        ConnManagerParams.setTimeout(httpParams, 10000);
        HttpConnectionParams.setConnectionTimeout(httpParams, 30000);
        HttpConnectionParams.setSoTimeout(httpParams, 30000);

        HttpClient httpClient = new DefaultHttpClient(httpParams);
        HttpPost httpPost = new HttpPost(BASE_URL);

        httpPost.setEntity(new ByteArrayEntity(request.toString()
                .getBytes()));
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();

        return EntityUtils.toString(httpEntity);

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
        System.out.println("UnsupportedEncodingException >>>>>>> "
                + e.getMessage());
    } catch (ClientProtocolException e) {
        e.printStackTrace();
        System.out.println("ClientProtocolException >>>>>>> "
                + e.getMessage());
    } catch (ConnectTimeoutException e) {
        Log.e("CONN TIMEOUT", e.toString());
        e.printStackTrace();

    } catch (SocketTimeoutException e) {
        Log.e("SOCK TIMEOUT", e.toString());
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
        System.out.println("IOException >>>>>>> " + e.getMessage());
    } catch (Exception e) {
        Log.e("OTHER EXCEPTIONS", e.toString());
        System.out.println("Exception >>>>>>> " + e.getMessage());
    }

Answer 2

解析服务器有一个内置的登录表，我们可以通过在该表中添加用户名和密码来使用此表，并按照此操作检查登录是否成功

ParseUser parseUser = new ParseUser();
                parseUser.logInInBackground( mEtUserName.getText().toString()
                        .trim()
                        ,mEtPswd.getText().toString(),new LogInCallback() {
                    @Override
                    public void done(ParseUser arg0, com.parse.ParseException arg1) {
                        if(arg1==null ){
                            startActivity(new Intent(LoginActivity.this,CaptureActivity.class));
                        } 
                        else{
                            arg1.printStackTrace();
                            Toast.makeText(LoginActivity.this,"UserName or Password is Incorrect", 0).show();
                        }
                    }
                });

为此我们必须首先使用以下代码

在解析中注册用户名和密码

HttpPost request = new HttpPost(SERVICE_URI);
            request.addHeader("X-Parse-Application-Id",
                    "e7ynC0ZB1ts5EQVpghywywoUUCNafT4XZnoJO3j5");
            request.addHeader("X-Parse-REST-API-Key",
                    "w9iInpo0kPmzibzjyCkhyjO199tc5V0vqtafL2yW");
            request.addHeader("Content-Type", "application/json");
            // Build JSON string
            JSONStringer TestApp = null;

            try {
                TestApp = new JSONStringer().object().key("username")
                        .value(mStrUname).key("password").value(mStrPswd).key("FullName").value(mStrFullName)
                        .endObject();
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();                   
            }

            StringEntity entity = null;

            try {
                entity = new StringEntity(TestApp.toString());
            } catch (UnsupportedEncodingException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            Log.d("****Parameter Input****", "Testing:" + TestApp);
            request.setEntity(entity);
            // Send request to WCF service
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpResponse response = null;

            try {
                response = httpClient.execute(request);
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            Log.d("WebInvoke", "Saving: " + response.getStatusLine().toString());
            // Get the status of web service
            BufferedReader rd = null;
            try {
                rd = new BufferedReader(new InputStreamReader(
                        response.getEntity().getContent()));
            } catch (IllegalStateException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            // print status in log
            String line = "";
            try {
                while ((line = rd.readLine()) != null) {
                    Log.d("****Status Line***", "Webservice: " + line);

                }
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            return null;
        }

Http响应不起作用

2 个答案: