Question

我正在使用此代码在服务器上上传图片..但作为回应我从我的网络服务获得此响应。为foreach（）提供的参数无效

-(IBAction)uploadToServer:(id)sender {
    NSString *videoURL = [[NSBundle mainBundle] pathForResource:@"1" ofType:@"jpeg"];
    NSData *videoData = [NSData dataWithContentsOfURL:[NSURL fileURLWithPath: videoURL]];
    AFHTTPClient *httpClient = [AFHTTPClient clientWithBaseURL:[NSURL URLWithString:@"http://youngdecade.com/test3/"]];

    NSMutableURLRequest *request = [httpClient multipartFormRequestWithMethod:@"POST" path:@"uploadmultipleimage.php" parameters:nil constructingBodyWithBlock:^(id <AFMultipartFormData>formData)
    {
        [formData appendPartWithFileData:videoData name:@"file" fileName:@"1.jpeg" mimeType:@"image/jpeg"];
    }];
    AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest: request];
    [operation
        setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) {
            NSLog(@"response string=%@",operation.responseString);
        }
        failure:^(AFHTTPRequestOperation *operation, NSError *error) {
            NSLog(@"Error : %@",  operation.responseString);
        }
    ];
    [operation start];
}

uploadmultipleimage.php：

<html lang="en">
    <head>
        <meta charset="UTF-8" />
        <title>Multiple File Ppload with PHP</title>
    </head>
    <body>
        <form action="uploadmultipleimage.php" method="post" enctype="multipart/form-data">
            <input type="file" id="file" name="file[]" multiple="multiple" accept="image/*" />
            <input type="submit" value="Upload!" />
        </form>
    </body>
</html>

如何在iPhone上的服务器上传图像？

0 个答案: