Question

新手在这里。两个按钮，note1和note2，在单击时将显示相同的AlertDialog，然后分开存储用户的选择。试图避免重复的代码我遇到问题，我很难有一个简单的方法，但我找不到它。感谢

@Override
public void onClick(View v) {
    // respond to clicks
    if (v.getId() == R.id.btnNote1) {
        AlertDialog.Builder builder = new AlertDialog.Builder(this);
        builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
                new DialogInterface.OnClickListener() {

                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        dialog.dismiss();
                        note1.setText(which);
                    }
                });
    }
    else if (v.getId() == R.id.btnNote2) {
        AlertDialog.Builder builder = new AlertDialog.Builder(this);
        builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
                new DialogInterface.OnClickListener() {

                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        dialog.dismiss();
                        note2.setText(which);
                    }
                });
    }

}

Answer 1

你可以在noteN.setText(which);语句之前将条件置于onClick函数中，因为这是两者之间唯一的变化。

Answer 2

你可以设置EditText（或者说note1和note2基于ID和按钮Listener中的用法。

@Override
public void onClick(View v) {
    // respond to clicks
    EditText note;
    if (v.getId() == R.id.btnNote1) {
        note = note1;
    } else {
        note = note2;
    }
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
            new DialogInterface.OnClickListener() {
                @Override
                public void onClick(DialogInterface dialog, int which) {
                    dialog.dismiss();
                    note.setText(which);
            }
            });
}

Answer 3

您可以创建一个最终的ViewID变量，以便您可以在onClick()

中引用它

@Override
public void onClick(View v) {
    final int viewID = v.getId();

    // respond to clicks
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
        new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
                dialog.dismiss();
                if(viewID == R.id.btnNote1) {
                    note1.setText(which);
                } else {
                    note2.setText(which);
                }
            }
        }
    );
}

Answer 4

@Override
public void onClick(View v) {
    // respond to clicks
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
            new DialogInterface.OnClickListener() {
                @Override
                public void onClick(DialogInterface dialog, int which) {
                    dialog.dismiss();
                    if (v.getId() == R.id.btnNote1)
                       note1.setText(which);
                    else
                       note2.setText(which);
                }
            });
}

Answer 5

如果您想对 OTHER 项目使用onClick（），请使用此方法。

@Override
public void onClick(View v) {
    // respond to clicks
    if (v.getId() == R.id.btnNote1 || v.getId() == R.id.btnNote2) {
       showAlerts(View v)
    }
}

private void showAlerts(View v)
{
     AlertDialog.Builder builder = new AlertDialog.Builder(this);
        builder.setTitle(R.string.selNoteBtn).setSingleChoiceItems(notes, 0,
                new DialogInterface.OnClickListener() {

                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        dialog.dismiss();
                        if(v.getId() == R.id.btnNote2)note2.setText(which);
                        else if(v.getId() == R.id.btnNote1)note1.setText(which);
                    }
      });
}

如何在这里避免重复的代码块

5 个答案: