我有以下简化的XML结构:
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<DESADV>
<M_DESADV>
<G_SG10>
<G_SG13>
<S_GIN>
<id>GIN</id>
<D_7405_6>BJ</D_7405_6>
<C_C208_2>
<D_7402_8>373500699550026556</D_7402_8>
</C_C208_2>
</S_GIN>
</G_SG13>
</G_SG10>
<G_SG10>
<G_SG17>
<S_PIA>
<id>PIA</id>
<D_4347>1</D_4347>
<C_C212_2>
<D_7140_2>110005</D_7140_2>
<D_7143_4>SA</D_7143_4>
</C_C212_2>
</S_PIA>
</G_SG17>
</G_SG10>
<G_SG10>
<G_SG17>
<S_PIA>
<id>PIA</id>
<D_4347>1</D_4347>
<C_C212_2>
<D_7140_2>123456</D_7140_2>
<D_7143_4>SA</D_7143_4>
</C_C212_2>
</S_PIA>
</G_SG17>
</G_SG10>
<G_SG10>
<G_SG13>
<S_GIN>
<id>GIN</id>
<D_7405_6>BJ</D_7405_6>
<C_C208_2>
<D_7402_8>3735009999999999</D_7402_8>
</C_C208_2>
</S_GIN>
</G_SG13>
</G_SG10>
<G_SG10>
<G_SG17>
<S_PIA>
<id>PIA</id>
<D_4347>1</D_4347>
<C_C212_2>
<D_7140_2>632154</D_7140_2>
<D_7143_4>SA</D_7143_4>
</C_C212_2>
</S_PIA>
</G_SG17>
</G_SG10>
<G_SG10>
<G_SG17>
<S_PIA>
<id>PIA</id>
<D_4347>1</D_4347>
<C_C212_2>
<D_7140_2>887796</D_7140_2>
<D_7143_4>SA</D_7143_4>
</C_C212_2>
</S_PIA>
</G_SG17>
</G_SG10>
</M_DESADV>
</DESADV>
我需要进行映射,以便获得以下XML输出:
<?xml version="1.0" encoding="UTF-8"?>
<list>
<number>373500699550026556 110005</number>
<number>373500699550026556 123456</number>
<number>3735009999999999 632154</number>
<number>3735009999999999 887796</number>
</list>
我无法获得该输出。我有以下XSLT,但我会工作:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="text()"/>
<xsl:template match="/">
<list>
<xsl:apply-templates/>
</list>
</xsl:template>
<xsl:template match="M_DESADV">
<xsl:for-each select="G_SG10/G_SG17/S_PIA/C_C212_2[D_7143_4='SA']/D_7140_2">
<number>
<xsl:value-of select="concat(
parent::C_C212_2/parent::S_PIA/parent::G_SG17/parent::G_SG10/parent::M_DESADV
/G_SG10/G_SG13/S_GIN[D_7405_6='BJ']/C_C208_2/D_7402_8,' ',
.)
"/>
</number>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
但是我的输出看起来像这不是我所期望的:
<?xml version="1.0" encoding="UTF-8"?>
<list>
<number>373500699550026556 110005</number>
<number>373500699550026556 123456</number>
<number>373500699550026556 632154</number>
<number>373500699550026556 887796</number>
</list>
这可以通过Muenchian Grouping解决吗?我尝试设置一个键,但它要么选择 “D_7402_8”或仅“D_7140_2”。
有人能告诉我如何解决这个问题吗? 感谢你并致以真诚的问候, 彼得
答案 0 :(得分:1)
我认为你不需要钥匙,你只需找到每个G_SG10
- 那个有一个G_SG17
,它最近的兄弟G_SG10
- 该-具有-α - G_SG13
:
<xsl:for-each select="G_SG10/G_SG17/S_PIA/C_C212_2[D_7143_4='SA']/D_7140_2">
<number>
<xsl:value-of select="concat(
ancestor::G_SG10/preceding-sibling::G_SG10[G_SG13][1]
/G_SG13/S_GIN[D_7405_6='BJ']/C_C208_2/D_7402_8,' ',
.)
"/>
</number>
</xsl:for-each>
如果真实XML中的条件比“有G_SG13
”更复杂,那么您只需要在preceding-sibling::
步骤的第一个谓词中对相关条件进行编码,例如
preceding-sibling::G_SG10[G_SG13/S_GIN/D_7405_6='BJ'][1]