如何异步使用HttpWebRequest(.NET,C#)?
答案 0 :(得分:121)
使用HttpWebRequest.BeginGetResponse()
HttpWebRequest webRequest;
void StartWebRequest()
{
webRequest.BeginGetResponse(new AsyncCallback(FinishWebRequest), null);
}
void FinishWebRequest(IAsyncResult result)
{
webRequest.EndGetResponse(result);
}
异步操作完成时调用回调函数。您至少需要从此功能中调用EndGetResponse()
。
答案 1 :(得分:64)
考虑答案:
HttpWebRequest webRequest;
void StartWebRequest()
{
webRequest.BeginGetResponse(new AsyncCallback(FinishWebRequest), null);
}
void FinishWebRequest(IAsyncResult result)
{
webRequest.EndGetResponse(result);
}
您可以发送请求指针或任何其他对象:
void StartWebRequest()
{
HttpWebRequest webRequest = ...;
webRequest.BeginGetResponse(new AsyncCallback(FinishWebRequest), webRequest);
}
void FinishWebRequest(IAsyncResult result)
{
HttpWebResponse response = (result.AsyncState as HttpWebRequest).EndGetResponse(result) as HttpWebResponse;
}
问候
答案 2 :(得分:59)
到目前为止,每个人都错了,因为BeginGetResponse()
在当前线程上做了一些工作。来自documentation:
BeginGetResponse方法需要一些同步设置任务 完成(DNS解析,代理检测和TCP套接字连接, 例如)此方法变为异步之前。结果是, 永远不应该在用户界面(UI)线程上调用此方法 因为它可能需要相当长的时间(最多几分钟) 根据网络设置)完成初始同步 在抛出错误的异常或方法之前设置任务 成功。
所以要做到这一点:
void DoWithResponse(HttpWebRequest request, Action<HttpWebResponse> responseAction)
{
Action wrapperAction = () =>
{
request.BeginGetResponse(new AsyncCallback((iar) =>
{
var response = (HttpWebResponse)((HttpWebRequest)iar.AsyncState).EndGetResponse(iar);
responseAction(response);
}), request);
};
wrapperAction.BeginInvoke(new AsyncCallback((iar) =>
{
var action = (Action)iar.AsyncState;
action.EndInvoke(iar);
}), wrapperAction);
}
然后,您可以通过响应执行所需操作。例如:
HttpWebRequest request;
// init your request...then:
DoWithResponse(request, (response) => {
var body = new StreamReader(response.GetResponseStream()).ReadToEnd();
Console.Write(body);
});
答案 3 :(得分:55)
到目前为止,最简单的方法是使用TaskFactory.FromAsync中的TPL。当与新的async/await关键字一起使用时,它实际上是几行代码:
var request = WebRequest.Create("http://www.stackoverflow.com");
var response = (HttpWebResponse) await Task.Factory
.FromAsync<WebResponse>(request.BeginGetResponse,
request.EndGetResponse,
null);
Debug.Assert(response.StatusCode == HttpStatusCode.OK);
如果您不能使用C#5编译器,则可以使用Task.ContinueWith方法完成上述操作:
Task.Factory.FromAsync<WebResponse>(request.BeginGetResponse,
request.EndGetResponse,
null)
.ContinueWith(task =>
{
var response = (HttpWebResponse) task.Result;
Debug.Assert(response.StatusCode == HttpStatusCode.OK);
});
答案 4 :(得分:7)
我最终使用了BackgroundWorker,它绝对是异步的,不像上面的一些解决方案,它处理返回GUI线程,而且很容易理解。
处理异常也非常容易,因为它们最终会出现在RunWorkerCompleted方法中,但请务必阅读:Unhandled exceptions in BackgroundWorker
我使用了WebClient,但显然你可以使用HttpWebRequest.GetResponse。
var worker = new BackgroundWorker();
worker.DoWork += (sender, args) => {
args.Result = new WebClient().DownloadString(settings.test_url);
};
worker.RunWorkerCompleted += (sender, e) => {
if (e.Error != null) {
connectivityLabel.Text = "Error: " + e.Error.Message;
} else {
connectivityLabel.Text = "Connectivity OK";
Log.d("result:" + e.Result);
}
};
connectivityLabel.Text = "Testing Connectivity";
worker.RunWorkerAsync();
答案 5 :(得分:5)
Task
:
private async Task<String> MakeRequestAsync(String url)
{
String responseText = await Task.Run(() =>
{
try
{
HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
WebResponse response = request.GetResponse();
Stream responseStream = response.GetResponseStream();
return new StreamReader(responseStream).ReadToEnd();
}
catch (Exception e)
{
Console.WriteLine("Error: " + e.Message);
}
return null;
});
return responseText;
}
使用异步方法:
String response = await MakeRequestAsync("http://example.com/");
<强>更新强>
此解决方案不适用于使用WebRequest.GetResponseAsync()
而非WebRequest.GetResponse()
的UWP应用,并且在适当情况下不会调用Dispose()
方法。 @dragansr有一个很好的替代解决方案来解决这些问题。
答案 6 :(得分:3)
public void GetResponseAsync (HttpWebRequest request, Action<HttpWebResponse> gotResponse)
{
if (request != null) {
request.BeginGetRequestStream ((r) => {
try { // there's a try/catch here because execution path is different from invokation one, exception here may cause a crash
HttpWebResponse response = request.EndGetResponse (r);
if (gotResponse != null)
gotResponse (response);
} catch (Exception x) {
Console.WriteLine ("Unable to get response for '" + request.RequestUri + "' Err: " + x);
}
}, null);
}
}
答案 7 :(得分:3)
public static async Task<byte[]> GetBytesAsync(string url) {
var request = (HttpWebRequest)WebRequest.Create(url);
using (var response = await request.GetResponseAsync())
using (var content = new MemoryStream())
using (var responseStream = response.GetResponseStream()) {
await responseStream.CopyToAsync(content);
return content.ToArray();
}
}
public static async Task<string> GetStringAsync(string url) {
var bytes = await GetBytesAsync(url);
return Encoding.UTF8.GetString(bytes, 0, bytes.Length);
}