Question

它不仅仅是一个变量，情况是这样的：

mysql_connect("localhost", "root", "") or die (mysql_error ());
mysql_select_db("tHofbrouwerijke") or die(mysql_error());
$strSQL = "SELECT * FROM bieren";
$rs = mysql_query($strSQL);
   while($row = mysql_fetch_array($rs)) 
    {echo "<form action='RemoveBier.php' method='POST'><button type='submit' name=".$row['Naam'].">Verwijderen</button> &nbsp &nbsp".$row['Naam']."<br>";}
echo "</form>";
?>

所以我使用了while循环从数据库中获取项目，我想使用按钮的名称来标识我必须删除的项目。当我进入“RemoveBier.php”页面并输入我认为正确的代码并尝试它时，它什么也没做。我的第二个php页面如下所示：

<?php 
include 'DeleteBier.php';
$NameButton=$row['Naam'];
mysql_connect("localhost", "root", "") or die (mysql_error ());
mysql_select_db("tHofbrouwerijke") or die(mysql_error());
echo $row['Naam'];
$strSQL = "DELETE FROM bieren WHERE naam = '.$_POST[$NameButton].'";
mysql_query($strSQL) or die(mysql_error());
header('Location: DeleteBier.php');
?>

Answer 1

<form method="post">
    <input type="hidden" name="Beer2delete" value="SOME BEERS NAME HERE" />
    <button>Submit</button>
</form>

您现在可以使用$_POST['Beer2delete']访问该名称。用户不会看到它，并且您有一致的名称可供参考。

如果您有多个选项，可以这样做：

<form method="post">
    <!-- HERE YOU LOOP, but the radiobutton so it will result in the following -->
    <input type="radio" name="beer2delete" value="beer 1" /> Beer 1 <br />
    <input type="radio" name="beer2delete" value="beer 2" /> Beer 2 <br />
    <input type="radio" name="beer2delete" value="beer 3" /> Beer 3 <br />
    <input type="radio" name="beer2delete" value="beer 4" /> Beer 4 <br />

    <input type="submit" name="DeleteBeer" value="Delete that delicious beer"/>
</form>

如何在另一个页面中获取变量？

1 个答案: