Question

我将此类型值存储在DB：

中

INPUT：

{
    "PatientProfile__is_recruiter": "1", 
    "PatientProfile__partner": "FMCS", 
    "PatientProfile__health_insurance_provider": "MILITARY/VA", 
    "PatientProfile__has_medical_home": "0", 
    "PatientProfile__medical_history_heart_disease": "0", 
    "PatientProfile__medical_history_hypertension": "0", 
    "data_model_name": [
        "PatientProfile"
    ]
}

当我尝试更新并在更新后，我发现了相同的结果，如：

{
    "PatientProfile__is_recruiter": "1", 
    "PatientProfile__partner": "FMCS", 
    "PatientProfile__health_insurance_provider": "MILITARY/VA", 
    "PatientProfile__has_medical_home": "0", 
    "PatientProfile__medical_history_heart_disease": "0", 
    "PatientProfile__medical_history_hypertension": "0", 
    "data_model_name": [
        "PatientProfile"
    ]
}

如果我没有更新此代码并获取db并尝试执行。我没有收到任何错误。当我尝试在更新后执行此代码时。我正在低于定义错误：

追踪（最近一次呼叫最后一次）：

  File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 111, in get_response
    response = callback(request, *callback_args, **callback_kwargs)

  File "/usr/local/lib/python2.6/dist-packages/django/contrib/auth/decorators.py", line 23, in _wrapped_view
    return view_func(request, *args, **kwargs)

  File "/home/ubuntu/django-apps/project_name/../project_name/apps/accounts/decorators.py", line 44, in inner_decorator
    return func(request, *args, **kwargs)

  File "/home/ubuntu/django-apps/project_name/../project_name/apps/reports/views.py", line 97, in hiv_report_new
    return form.get_itable(pk)

  File "/home/ubuntu/django-apps/project_name/../project_name/apps/reports/forms.py", line 454, in get_itable
    custom_data =  ast.literal_eval(report_qs[0]['query'])

  File "/usr/lib/python2.6/ast.py", line 49, in literal_eval
    node_or_string = parse(node_or_string, mode='eval')

  File "/usr/lib/python2.6/ast.py", line 37, in parse
    return compile(expr, filename, mode, PyCF_ONLY_AST)

  File "<unknown>", line 1

    {


^

SyntaxError: invalid syntax

Answer 1

请使用json在dict

中存储list或db

例如。

存储时

obj = json.dumps("{
    'PatientProfile__is_recruiter': '1', 
    'PatientProfile__partner': 'FMCS', 
    'PatientProfile__health_insurance_provider': 'MILITARY/VA', 
    'PatientProfile__has_medical_home': '0', 
    'PatientProfile__medical_history_heart_disease': '0', 
    'PatientProfile__medical_history_hypertension': '0', 
    'data_model_name': [
        'PatientProfile'
    ]
}")

并存储json obj，即obj

并在检索使用时

json.loads

所以你会得到它之前保存在db ..

中的内容

：）

Answer 2

存储时使用json.dumps：

obj = json.dumps("{
'PatientProfile__is_recruiter': '1', 
'PatientProfile__partner': 'FMCS', 
'PatientProfile__health_insurance_provider': 'MILITARY/VA', 
'PatientProfile__has_medical_home': '0', 
'PatientProfile__medical_history_heart_disease': '0', 
'PatientProfile__medical_history_hypertension': '0', 
'data_model_name': ['PatientProfile']
}")

检索时你有两个选择，即

示例：

>>>simplejson.loads('{"x":"y"}') 
{'x': 'y'}


>>> json.loads('{"x":"y"}') 
{u'x': u'y'}

即。如果字符串是ASCII，simplejson返回bytestrings（它返回否则为unicode对象），而json总是返回unicode对象。

当我尝试更新django中的表单时遇到此类问题

2 个答案: