Question

我试图创造一个井字游戏;但我有一点点麻烦。我创建了一个包含数字的列表，因此当选择该数字时，它会更改为x或o。然而，当我的电路板打印时，它的数字为0,1,2,3,4,5,6,7,8，我不希望它们是这样的。我的问题是如何更改空列表中的字符？我会使用索引还是有另一种方法

board = [0,1,2,
         3,4,5,
         6,7,8]

def gameBoard():
    print("    " "a" "   " "b" "   " "c")
    print("  ""-------------")
    print(("1"),("|"),board[0],"|",board[1], "|" ,board[2], "|")
    print("  ""-------------")
    print(("2"),("|"),board[3],"|",board[4], "|" ,board[5], "|")
    print("  ""-------------")   
    print(("3"),("|"),board[6],"|",board[7], "|" ,board[8], "|")
    print("  ""-------------")    


while True:
    user_input = input("Enter your move: ")
    if user_input == "a1":
        user_input = "0"
    elif user_input == "a2":
        user_input = "3" 
    elif user_input == "a3":
        user_input="6"
    elif user_input == "b1":
        user_input = "1"
    elif user_input == "b2":
        user_input = "4"
    elif user_input== "b3":
        user_input = "7"
    elif user_input == "c1":
        user_input = "2"
    elif user_input == "c2":
        user_input = "5"
    elif user_input == "c3":
        user_input = "8"
    else:
        print("invalid coordinates")
    user_input= int(user_input)

Answer 1

我猜你想要的是一个带字符串的电路板，而不是数字，最初用单个空格的字符串填充。您可以为此电路板或二维数组使用单个列表

单一列表实施

board = [" "," "," "," "," "," "," "," "," "]

来自控制台的示例：

>>> board = [" "," "," "," "," "," "," "," "," "]
>>> board[2] = "X"
>>> board
[' ', ' ', 'X', ' ', ' ', ' ', ' ', ' ', ' ']
>>> board[0]
' '
>>> board[2]
'X'
>>>

二维数组实现

board = [[" "," "," "],[" "," "," "],[" "," "," "]]

来自控制台的示例：

>>> board = [[" "," "," "],[" "," "," "],[" "," "," "]]
>>> board[1][2] = "O"
>>> board
[[' ', ' ', ' '], [' ', ' ', 'O'], [' ', ' ', ' ']]
>>> board[0][1]
' '
>>> board[1][2]
'O'

打印2D列表的示例：

>>> board = [["X"," ","X"],[" ","X"," "],["X"," ","X"]]
>>> for row in board:
    string = ""
    for element in row:
        string = string + element
    print(string)


X X
 X 
X X

Answer 2

使用二维列表！

board = [[0,0,0],
         [0,0,0],
         [0,0,0]]

然后只使用您想要的值等。然后参考只是：

board[row][column]

编辑：我有点误读了这个问题，而不是0到9，你可以把它们都变成空字符串，即。

board[i] = ''

或使用字典将数字映射到字符串

board[5] = ''

Answer 3

您可以使用字典：

board = {0:'X', 1:'O', 2:' ',
         3:'X', 4:'O', 5:' ',
         6:'X', 7:'O', 8:' ',
        }

print board[1] # will print O
board[1] = 'X'
print board[1] # will print X

Answer 4

您的问题并不完全是因为您没有在每次迭代时更新游戏板。但是，这里有一些建议：

将初始板设置为零（或“O”）
如果您使用的是列表，则user_input = '1'等所有语句都可以设置为use_input = 1，以避免显式调用int。
您可以通过简单地说board[user_input] = 'X'或board[user_input] = 'O'来更改列表的值，具体取决于播放器。

Answer 5

从您的代码中，您填写的板有0 - 8。如果您检查板[7]它将返回7。

我认为你想用空格初始化电路板，因此电路板[7]将返回''（空格）。

你可以做板= [''，''，''，''，''，''，''，''，'']

或者更干净，

board = [''] * 9

希望这会有所帮助:) 使用矩阵对于实现来说也不是一个坏主意，但与您尝试解决的问题不同

如何实现列表

5 个答案: