Question

如何编写if语句来检查infowindow是否打开，如果是，则在单击它或其他标记时将其关闭。我的代码在下面！

function add_marker( $marker, map ) {

// var
var latlng = new google.maps.LatLng( $marker.attr('data-lat'), $marker.attr('data-lng') );

// create marker
var marker = new google.maps.Marker({
    position    : latlng,
    map         : map
});

// add to array
map.markers.push( marker );

// if marker contains HTML, add it to an infoWindow
if( $marker.html() )
{
    // create info window
    var infowindow = new google.maps.InfoWindow({
        content     : $marker.html()
    });

    // show info window when marker is clicked
    google.maps.event.addListener(marker, 'click', function() {

        infowindow.open( map, marker );

    });
}

}

Answer 1

根据问题中的代码，它会是这样的，虽然它未经测试：

google.maps.event.addListener(marker, 'click', function() {
    var map = infoWindow.getMap();
    if (map !== null && typeof map !== "undefined") {
        infowindow.close();
    } else {
        infowindow.open( map, marker );
    }
});

Answer 2

function fun_name() 
{
  //create the global instance of infoWindow 
  if(!window.infowindow)
  {
    window.infowindow=new google.maps.InfoWindow();
  }
    -------
    -------
    -------

 google.maps.event.addListener(marker, 'click', function() {
    infowindow.close();
    infowindow.setContent(box_html);
    infowindow.open(map,this)
  });

}

如果打开，请单击关闭地图信息窗口

2 个答案: