Question

我创建了一个用于搜索MySQL数据库的php搜索脚本，但没有搜索返回结果。

表格代码

<form method="post" action="search.php">
<input type="text" value="Search..." name="query" />
<input type="submit" value="Find" name="completedsearch" />
</form>

PHP脚本

<?php
                    if(isset($_POST['completedsearch']))
                    {
                            $term = $_POST['query'];
                            $mysql = mysql_connect("localhost","searchuser","password");
                            mysql_select_db("hcsd");
                            $qu = mysql_query("SELECT * FROM your_table WHERE COMPANY LIKE '%{$term}%' OR LOCATION LIKE '%{$term}%' OR KEYWORDS LIKE '%{$term}%' OR PRODUCTSSERVICES LIKE '%{$term}%' ");
                            echo "
                                            <th>Name</th>
                                            <th>Location</th>
                                            <th>Products/Services</th>
                                            ";
                            while($row = mysql_fetch_array($qu))
                                       {

                                            echo "<tr><td>";  
                                            echo $row['COMPANY'];
                                            echo "</td>";
                                            echo "<td>";
                                            echo $row['LOCATION'];
                                            echo "</td>";
                                            echo "<td>";
                                            echo $row['PRODUCTSSERVICES'];
                                            echo "</tr></td>";
                            }
                    }
            ?>

MySQL数据库有4列，标题为COMPANY，LOCATION，KEYWORDS＆amp; PRODUCTSSERVICES，这个脚本应该搜索搜索词的任何列，然后显示表中任何匹配行的COMPANY，LOCATION和PRODUCTSSERVICES，甚至使用搜索词我知道100％在MySQL表中，我是仍未收到任何结果。

Answer 1

我不确定花括号在这里有帮助......

替换

 $qu = mysql_query("SELECT * FROM your_table WHERE COMPANY LIKE '%{$term}%' OR LOCATION LIKE '%{$term}%' OR KEYWORDS LIKE '%{$term}%' OR PRODUCTSSERVICES LIKE '%{$term}%' ");

使用

 $qu = mysql_query("SELECT * FROM your_table WHERE COMPANY LIKE '%".$term."%' OR LOCATION LIKE '%".$term."%' OR KEYWORDS LIKE '%".$term."%' OR PRODUCTSSERVICES LIKE '%".$term."%'");

您也应该转义输入

 $qu = mysql_query("SELECT * FROM your_table WHERE COMPANY LIKE '%".mysql_real_escape_string($term)."%' OR LOCATION LIKE '%".mysql_real_escape_string($term)."%' OR KEYWORDS LIKE '%".mysql_real_escape_string($term)."%' OR PRODUCTSSERVICES LIKE '%".mysql_real_escape_string($term)."%'");

还要考虑使用更新的mysqli_ functions

Answer 2

你的桌子叫什么名字？

您应该在phpmyadmin或用于管理数据库的任何软件中尝试您的请求并查看结果。如果不是结果，则您的请求中可能存在错误。

PHP MySQL搜索没有返回结果

2 个答案: