Question

我有以下PHP代码：

//Selecting amount from rcpts_exp table
$query = "SELECT amount from rcpts_exp";
$result = mysql_query($query);
if(!$result){
    echo "FAILED";
}
$num = mysql_num_rows($result);

//fetching each row
for($i=0;$i<$num;$i++){
$row = mysql_fetch_assoc($result);
//Simple Mathematics 
$a_b_t = $row['amount'] / 1.16;
$t = $a_b_t * 0.16;

//--------------------------------For Testing Output
//echo $row['amount']."<br />";
//echo "ABT = ". $a_b_t = number_format($a_b_t,2)."<br />";
//echo "tax = ".$t  = number_format($t,2)."<br />";
//-------------------------------End Testing

//Update the values into rcpts_exp for each amount
$query2 = "UPDATE rcpts_exp SET amount_before_tax = '".$a_b_t."', tax = '".$t."' WHERE amount = '".$row['amount']."'";
$result2 = mysql_query($query2);
if(!$result2){
echo "Update Failed";
mysqli_error();
}

}

“测试”部分完美地输出所需的结果，它将$row['amount']除以1.16，然后将下一个乘以0.16。因此，考虑到输出正确，问题将转向UPDATE部分.-它可能会将amount_before_tax和tax列更新为0.00，或者跳过默认值，如mysql中所定义。 / p>

我的表结构如下：

id - int（11）AI
金额 - 浮动（10,2）
amount_before_tax - float（10,2）
tax - float（10,2）

请帮助！

Answer 1

您不要在数字字段周围放置单引号：

试试这个：

$query2 = "UPDATE rcpts_exp SET amount_before_tax = ".$a_b_t.", tax = ".$t." WHERE amount = ".$row['amount'];

PHP失败更新现有记录

1 个答案: