Question

我有一名班级员工

#include <iostream>
#include <string>
using namespace std;

class employee
{
    public:

            double operator + (employee);
            employee operator + (employee);
            employee(int);
            double getSalary();

    private:

           double salary;

};

int main()
{  
  employee A(400);
  employee B(800);

  cout<<A+B;

  employee C = A+B; //overload + operator to add 2 object together

  cout<<C.getSalary();

}

employee::employee(int salary)
{
    this->salary = salary;
}


double employee::operator + (employee e)
{
    double total;

    total = e.salary + this->salary;

    return total;    
}

employee employee::operator + (employee e)
{

    double total;

    total= this->salary + e.salary;

    employee c(total);

    return c;


}

double employee::getSalary()
{
    return this->salary;
}

我正在尝试重载+运算符以使用2个员工对象，因此我可以将它们一起添加但我收到编译器错误

员工操作员+（员工）不能超载;

我不明白为什么以及如何重载+运算符以添加同一类的2个对象

Answer 1

你有两个运算符+具有不同的返回类型但是相同的参数，因此编译器无法分辨使用哪一个。所以对于这个例子，因为你不能“添加”两个雇员我只使用一个操作员：

class employee
{
    public:
            //you only need one + operator
            double operator + (const employee & e)const;
            //constructor is taking a double so that your code works.
            employee(double);
    private:
           double salary;
};

double operator + (const employee & e)const
{
    return salary + e.salaty;    
}
employee::employee(double s)
    :salary(s)
{
}

其余代码是相同的。

Answer 2

你不能在返回类型的基础上重载运算符..

除此之外，您的代码还有一个问题。你需要重载＆lt;＆lt;运算符采用'employee'类型的右手操作数

无法重载+运算符以添加2个对象

2 个答案: