如何确定列表中最常见的月份？

Question

假设我有一个下雨日期的日期列表。

rained=["01-05-2012","05-01-2012","01-12-2012","06-14-2013"]

日期的顺序是月，日，年。从列表中可以看出，在这些日期中，一月份（01）下雨最多。我怎样才能为此创建代码？

Answer 1

使用collections.Counter：

>>> rained=["01-05-2012","05-01-2012","01-12-2012","06-14-2013"]
>>> from collections import Counter
>>> Counter(x[:2] for x in rained).most_common()[0][0]
'01'

most_common()将按降序返回项目元组列表和计数：

>>> Counter(x[:2] for x in rained).most_common()
[('01', 2), ('06', 1), ('05', 1)]

Answer 2

使用split（）函数按符号' - '拆分列表中的每个项目，然后分析您可以得到答案的月份。

Answer 3

如果有平局，你可以做这样的事情

>>> rained=["01-05-2012", "05-01-2012", "01-12-2012", "06-14-2013"]
>>> from collections import Counter
>>> counts = Counter(x[:2] for x in rained).most_common()
>>> [i for i, j in counts if j==counts[0][1]]
['01']

这是一个带有平局的例子

>>> rained=["01-05-2012", "05-01-2012", "01-12-2012", "06-14-2013", "06-12-2013"]
>>> counts = Counter(x[:2] for x in rained).most_common()
>>> [i for i, j in counts if j==counts[0][1]]
['01', '06']