Question

我试图通过使用二维数组和嵌套循环来打印出三个月的12个月的销售额。我很迷惑。有人可以告诉我使用这些方法我的代码出错了吗。我不想要替代品。

#include "stdafx.h"
#include <iostream>
#include <string>

using namespace std;
int x = 0;
int v = 0;
int y = 0;
int sum = 0;
const int year = 3;
const int month = 12;

int _tmain(int argc, _TCHAR* argv[])
{
    int sales[year][month];
    char * date[12] = {"january", "february", "march", "april", "may", "june", "july", "august", "september", "october", "november", "december"};
    for(int z = 0; z < 3; z++)
    {
        {
            cin >> v;
            sales * year[z] = v;
        }

        for(int x = 0; x < 12; x++)
        {
            cout << "Please enter the sales for month " << date[x] << ":\n";
            cin >> y;
            sales * month[x] = y;
            sum += y;
        }
    }
    cout << "There are the sales of the c++ crook: \n";

    cout << sales[3][12] << endl;
    //cout << "Month 1 = " << year[0] << "   " << month[0] << endl;
    //cout << "Month 2 = " << year[0] << "   " << month[1] << endl;
    //cout << "Month 3 = " << year[0] << "   " << month[2] << endl;
    //cout << "Month 4 = " << year[0] << "   " << month[3] << endl;
    //cout << "Month 5 = " << year[0] << "   " << month[4] << endl;
    //cout << "Month 6 = " << year[0] << "   " << month[5] << endl;
    //cout << "Month 7 = " << year[0] << "   " << month[6] << endl;
    //cout << "Month 8 = " << year[0] << "   " << month[7] << endl;
    //cout << "Month 9 = " << year[0] << "   " << month[8] << endl;
    //cout << "Month 10 = " << year[0] << "   " << month[9] << endl;
    //cout << "Month 11 = " << year[0] << "   " << month[10] << endl;
    //cout << "Month 12 = " << year[0] << "   " << month[11] << endl;

    //cout << "Month 1 = " << year[1] << "   " << month[0] << endl;
    //cout << "Month 2 = " << year[1] << "   " << month[1] << endl;
    //cout << "Month 3 = " << year[1] << "   " << month[2] << endl;
    //cout << "Month 4 = " << year[1] << "   " << month[3] << endl;
    //cout << "Month 5 = " << year[1] << "   " << month[4] << endl;
    //cout << "Month 6 = " << year[1] << "   " << month[5] << endl;
    //cout << "Month 7 = " << year[1] << "   " << month[6] << endl;
    //cout << "Month 8 = " << year[1] << "   " << month[7] << endl;
    //cout << "Month 9 = " << year[1] << "   " << month[8] << endl;
    //cout << "Month 10 = " << year[1] << "   " << month[9] << endl;
    //cout << "Month 11 = " << year[1] << "   " << month[10] << endl;
    //cout << "Month 12 = " << year[1] << "   " << month[11] << endl;
    //cout << "The annual sales for c++ crook is: " << sum << " ;]";
    cin.get();
    cin.get();


    return 0;
}

Answer 1

有几件事：

1）你想确保表达式左侧的东西是有效的＆＃34;左值＆＃34; - 也就是说，它转换为可以存储评估RHS结果的位置。像

这样的一行

sales *month[x] = v;

不符合要求。

另一个错误：当你声明数组

时

sales[year][month];

您需要确保year和month都存在（已声明）并且具有有效值（可能是3和12？） - 你有一个名为date的数组，但你指的是

中的month

sales * month[x] = v;

正如我所提到的，你不能只是在等式的左边乘以东西。你可以考虑

sales[year][month] = v;

在您的情况下，您的外圈z从0变为2， - 可能是您的year;内循环从0变为11所以我认为这是月份。然后你可以做

sales[z][x] = y;

您可能实际上想要记录这些销售数字适用于＆＃34;的年份，在这种情况下您需要创建一个数组

salesYears[3];

并存储年份的价值。在您期望输入时提示用户是一个非常好的主意 -

std::cout << "Please enter the year of the sales" << std::endl;

等

这些只是一些指示。你的代码真的很乱。记住：

Declare all variables
Make sure all arrays are the right size
Prompt for inputs
Check that inputs are valid
Address 2D arrays with arrayName[index1][index2]
Thing on left hand side of equation must be "valid lvalue"
You might need additional variables to store both the year and the sales

二维数组和嵌套循环

1 个答案: