构造函数的void修饰符导致异常

Question

public class This_testing {

    int x,y;

    public This_testing(int x,int y){  //Why modifier void here would cause exception?
        this.x=x;
        this.y=y;
    }

    public static void main(String [] args){
        This_testing t =new This_testing(40,50);
        System.out.println(t.x+" "+t.y);
    }
}

为什么对构造函数使用修饰符void This_testing会导致以下异常：

Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - 
constructor This_testing in class practice.This_testing cannot be applied to given types;
  required: no arguments
  found: int,int
  reason: actual and formal argument lists differ in length
    at practice.This_testing.main(This_testing.java:13)

Answer 1

构造函数不返回任何内容，甚至不返回void。它只是如何在语言规范中定义它们。

您可以创建一个名为This_testing的方法，它返回void，但这将被视为方法，而不是构造函数（因此，使用new This_testing(x, y)将无法编译）。