Question

所以这可能不是那么难，但我有点难过。我有一个按钮，它是一个较大的控制面板中的“拍照”按钮。现在LED翻转10秒然后翻转。我希望它在前5秒闪烁，然后在最后5秒保持稳定。不知道怎么做，我已经尝试了一些猜测，但没有去。这是我到目前为止所拥有的，它目前漫长而丑陋：

// take a picture button


const int shoot_pin = 5;
const int shoot_led = 13; 

int shoot_state = 0;
int last_shoot_state = 0;


long shoot_timer;
long lastDebounceTime = 0;  // the last time the output pin was toggled
long debounceDelay = 10;    // the debounce time; increase if the output flickers


void setup(){
   Serial.begin(9600);
   pinMode(shoot_pin, INPUT);
   pinMode(shoot_led, OUTPUT);

}

void loop() {
  int shoot_reading = digitalRead(shoot_pin);

  if (shoot_reading != last_shoot_state) { lastDebounceTime = millis(); } 

  if ((millis() - lastDebounceTime) > debounceDelay) {

    if (shoot_reading != shoot_state) {
      shoot_state = shoot_reading;

      if (shoot_state == HIGH) {
          digitalWrite(shoot_led, HIGH);
          shoot_timer = millis();
          Serial.println("Counting down...5 seconds"); // for tracking
          delay(5000);
          Serial.println("Shooting Picture"); // for tracking - eventually will be a keypress

      } // end of high

    } // end of reading

  }// end of that giant nested debaounce

  last_shoot_state = shoot_reading;

  // right now just stays lit for 10 seconds
  if (millis() - shoot_timer >= 10000){ digitalWrite(shoot_led, LOW);}

} // end of loop

Answer 1

通过调用为您闪烁的自定义函数来替换您的延迟（在这种情况下为blinkLED），然后将开启时间从10秒减少到5

// take a picture button


const int shoot_pin = 5;
const int shoot_led = 13; 

int shoot_state = 0;
int last_shoot_state = 0;


long shoot_timer;
long lastDebounceTime = 0;  // the last time the output pin was toggled
long debounceDelay = 10;    // the debounce time; increase if the output flickers


void setup(){
   Serial.begin(9600);
   pinMode(shoot_pin, INPUT);
   pinMode(shoot_led, OUTPUT);

}

void loop() {
  int shoot_reading = digitalRead(shoot_pin);

  if (shoot_reading != last_shoot_state) { lastDebounceTime = millis(); } 

  if ((millis() - lastDebounceTime) > debounceDelay) {

    if (shoot_reading != shoot_state) {
      shoot_state = shoot_reading;

      if (shoot_state == HIGH) {
          digitalWrite(shoot_led, HIGH);
          shoot_timer = millis();
          Serial.println("Counting down...5 seconds"); // for tracking
          delay(5000);
          blinkLED(13, 500, 500, 5);
          Serial.println("Shooting Picture"); // for tracking - eventually will be a keypress

      } // end of high

    } // end of reading

  }// end of that giant nested debounce

  last_shoot_state = shoot_reading;

  // turn on LED for 5 seconds
  digitalWrite(shoot_led, LOW);
  delay(5000);
  digitalWrite(shoot_led, HIGH);

} // end of loop

void blinkLED(int pinNumber, int onLength, int offLength, int repetitions){
    for(int i=0; i < repetitions; i++){    
        digitalWrite(pinNumber, LOW); //on
        delay(onLength);
        digitalWrite(pinNumber, HIGH); //off
        delay(offLength);
    }
}

前5秒闪烁LED，按下按钮时保持稳定最后5秒（Arduino）

1 个答案: