如果Unix脚本包含单行，则删除多个文件

Question

#!/bin/bash
LINECOUNT=wc -l 111.txt | cut -f8 -d' '
if [[ $LINECOUNT == 1 ]]; then rm -f 111.txt fi

如何处理多个文件？请指教。

Answer 1

您需要for循环来迭代所需的文件：

for f in *.txt; do   # All file ending in '.txt' in the current directory
    LINECOUNT=$( wc -l < "$f" )
    if [[ $LINECOUNT == 1 ]]; then
        rm "$f"
    fi
done