Crawler4j ImageCrawler String args

Question

我正在尝试启动crawler4j示例： crawler4j

当我启动ImageCrawlController时，我已经在第一步失败了args.length＆lt; 3，因为它的0.我怎么能确定args比3大？

public class ImageCrawlController {
  public static void main(String[] args) throws Exception {
    if (args.length < 3) {
      System.out.println("Needed parameters: ");
      System.out.println("\t rootFolder (it will contain intermediate crawl data)");
      System.out.println("\t numberOfCralwers (number of concurrent threads)");
      System.out.println("\t storageFolder (a folder for storing downloaded images)");
      return;
    }
  }
}

Answer 1

  

'...如何在args的main函数中放置一个值？该   main函数始终以args = 0开头。'

日食：RUN-＆gt;运行配置。在左侧菜单中选择Java应用程序。现在选择标签：ARGUMENTS。

你可以打电话给他们：System.out.println(args[1]); ///<-2