我有一个自定义类型的arraylist。在C中,我可以找出数组或变量存储在内存中的位置,然后将该部分内存保存到文件中,然后再将其直接加载到数组/变量中。
我如何在Java中实现这一点,有一种简单的方法吗?
答案 0 :(得分:0)
关键字是序列化。 List中的元素需要实现Serializable接口,以及该类中的所有元素。
static class Baz implements Serializable {
private static final long serialVersionUID = 1L;
int i;
String s;
public Baz(int i, String s) { this.i = i; this.s = s; }
}
@Test
public void serAL() throws FileNotFoundException, IOException, ClassNotFoundException {
List<Baz> list = Arrays.asList(new Baz(1, "one"), new Baz(2, "two"), new Baz(3, "three"));
try (ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream("al.dat"))) {
oos.writeObject(list);
}
try (ObjectInputStream ois = new ObjectInputStream(new FileInputStream("al.dat"))) {
@SuppressWarnings("unchecked")
List<Baz> serAL = (List<Baz>) ois.readObject();
Assert.assertEquals(3, serAL.size());
Assert.assertEquals(1, serAL.get(0).i);
Assert.assertEquals("one", serAL.get(0).s);
Assert.assertEquals(2, serAL.get(1).i);
Assert.assertEquals("two", serAL.get(1).s);
Assert.assertEquals(3, serAL.get(2).i);
Assert.assertEquals("three", serAL.get(2).s);
}
}
答案 1 :(得分:0)
static class Foo{
String name;
Foo() {
}
Foo(String name) {
this.name = name;
}
@Override
public String toString() {
final StringBuilder sb = new StringBuilder("Foo{");
sb.append("name='").append(name).append('\'');
sb.append('}');
return sb.toString();
}
}
public static void main(String[] args) {
Kryo kryo = new Kryo();
Output output = new Output(100);
List<Foo> foos = Arrays.asList(new Foo("foo1"), new Foo("foo2"), new Foo("foo3"));
kryo.writeObject(output, foos.subList(1, 3));
List<Foo> foosAfter = kryo.readObject(new Input(output.toBytes()), ArrayList.class);
System.out.println("before: " + foos);
System.out.println("after: " + foosAfter);
System.out.println("bytes: " + Arrays.toString(output.toBytes()));
}
输出:
before: [Foo{name='foo1'}, Foo{name='foo2'}, Foo{name='foo3'}]
after: [Foo{name='foo2'}, Foo{name='foo3'}]
bytes: [1, 2, 1, 0, 99, 104, 97, 115, 99, 104, 101, 118, 46, 117, 116 ...