Question

我正在努力解决以下这个问题。我在资源目录中的样式文件。但它不能将click方法应用于上下文菜单项。它显示在此错误下方。请帮助我如何实现这一目标。

错误：“'无法在文本'OnMenuItemClick'中创建'点击'。'行号“10”和行位置“35”。“

    <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
                xmlns:src="clr-namespace:System;assembly=mscorlib"
                xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
<ObjectDataProvider x:Key="date" ObjectType="{x:Type src:DateTime}"/>
<Style x:Key="ContextMenuStyle1" TargetType="{x:Type ContextMenu}">
    <Setter Property="BorderThickness" Value="0"/>
    <Setter Property="BorderBrush" Value="Transparent"/>
</Style>
<ContextMenu x:Key="ListViewContext" Style="{StaticResource ContextMenuStyle1}">
    <MenuItem Header="Create" Click="OnMenuItemClick" CommandParameter="{Binding RelativeSource={RelativeSource AncestorType={x:Type ContextMenu}}}"></MenuItem>
</ContextMenu>
<ContextMenu x:Key="GridItemContext" Style="{StaticResource ContextMenuStyle1}">
    <MenuItem Header="Modify" CommandParameter="{Binding RelativeSource={RelativeSource AncestorType={x:Type ContextMenu}}}"/>
    <MenuItem Header="Delete" CommandParameter="{Binding RelativeSource={RelativeSource AncestorType={x:Type ContextMenu}}}"/>
</ContextMenu>
<Style x:Key="ListViewGrid" TargetType="{x:Type ListView}">
    <Setter Property="BorderBrush" Value="#FFDFDFE2"/>
    <Setter Property="BorderThickness" Value="1"/>
    <Setter Property="Background" Value="#faf2f2"/>
    <Setter Property="ContextMenu" Value="{StaticResource ListViewContext}"/>
</Style>
<Style TargetType="{x:Type ListViewItem}">
    <Setter Property="ContextMenu" Value="{StaticResource GridItemContext}"/>
    <Setter Property="Template">
        <Setter.Value>
            <ControlTemplate TargetType="ListViewItem">
                <Border CornerRadius="0" SnapsToDevicePixels="True"  >
                    <Border Name="InnerBorder" CornerRadius="0" BorderThickness="0,0,0,1" BorderBrush="#FFDFDFE2">
                        <Grid Background="#FFEFEFEF" Name="Trg" Height="20">
                            <GridViewRowPresenter />
                        </Grid>
                    </Border>
                </Border>
                <ControlTemplate.Triggers>
                    <Trigger Property="IsMouseOver" Value="True">
                        <Setter TargetName="Trg" Property="Background" Value="#FFDFDFE2" />
                    </Trigger>
                    <Trigger Property="IsSelected" Value="True">
                        <Setter TargetName="Trg" Property="Background" Value="#FFDFDFE2" />
                    </Trigger>
                    <MultiTrigger>
                        <MultiTrigger.Conditions>
                            <Condition Property="IsSelected" Value="True" />
                            <Condition Property="IsMouseOver" Value="True" />
                        </MultiTrigger.Conditions>
                    </MultiTrigger>
                </ControlTemplate.Triggers>

            </ControlTemplate>
        </Setter.Value>
    </Setter>
</Style>

Answer 1

当我尝试上面的代码时，我得到的错误是：

错误1“ResourceDictionary”根元素需要x：Class属性支持XAML文件中的事件处理程序。删除事件 Click事件的处理程序，或者向根添加x：Class属性元件。第10行第35位

这就是我修复它的方法：

1）在ResourceDictionary：

中添加了x：Class属性

x:Class="WpfApplication4.Dictionary1"

2）在项目中添加了一个C＃类文件，代码如下：

public partial class Dictionary1 : ResourceDictionary
{
    public Dictionary1()
    {
        InitializeComponent();
    }

    void OnMenuItemClick(object sender, RoutedEventArgs e)
    {

    }
}

然后，项目建好了。

无法在资源目录中创建menuitem click方法

1 个答案: