我的字符串包含前导和尾随空格(见下文)。
当我应用LRTIM功能时,它似乎工作。接下来,当我将带有LEN函数的LTRIM函数嵌套到字符串时,看起来长度偏离1(即原始字符串的长度为16,LTRIM从字符串中删除了单个(1)前导空格,所以我期待LEN返回15的长度,而不是14)。有什么解释吗?
SELECT
' This is a test ' AS origStr
,LEN(' This is a test ') AS origStrLen
,'[' + LTRIM(' This is a test ') + ']' AS ltrimStr
,LEN(LTRIM(' This is a test ')) AS strLtrimLen
;
结果:
This is a test | 16 | [This is a test ] | 14 |
答案 0 :(得分:0)
这是因为len()在字符串空格后不计算。
LEN(LTRIM(' This is a test ')) has one space before and one space after string.
实施例:
SELECT LEN('TEXT ')
退货---> 4