Question

我使用FileSystemWatcher通知文件更改，然后创建该文件的副本：

$watcher = New-Object System.IO.FileSystemWatcher
$watcher.Path = "C:\Orders\"
$watcher.IncludeSubdirectories = $false
$watcher.EnableRaisingEvents = $true

$changed = Register-ObjectEvent $watcher "Changed" -Action {
   write-host "Changed: $($eventArgs.FullPath)"
   $datestamp = get-date -uformat "%Y%m%d%H%M%S" 
   write-host $datestamp
   copy-item $eventArgs.FullPath "$(watcher.Path)backup-$datestamp"
}

因此，如果更改C:\Orders\orders.xml，则应创建C:\Orders\backup-20131125121004。但是，这不起作用，并且不会产生错误。通知确实有效，而不是副本：

Windows PowerShell
Copyright (C) 2009 Microsoft Corporation. All rights reserved.

PS C:\Documents and Settings\sladministrator\Desktop> .\WatchBizSyncOrders.ps1
PS C:\Documents and Settings\sladministrator\Desktop> Changed: C:\Orders\New Text Document.txt
20131125100821

Answer 1

改变这个：

$(watcher.Path)backup-$datestamp"

到

$($sender.Path)backup-$datestamp"

请注意$()内的变量仍然需要$。 $sender自动变量将始终包含生成事件的对象。

使用PowerShell在更改时复制文件

1 个答案: