Question

只想打印从开始到结束点的那些

示例：

Started at Mon Nov 25 14:30:02 ALMT 2013
Load average for db1 is 10 which is less than 100
Load average for db2 is 3 which is less than 100
Load average for db3 is 6 which is less than 100
Load average for db4 is 5 which is less than 100
Load average for db5 is 5 which is less than 100
Mon Nov 25                                                                                 page
some other data
some other data
some other data

预期：

Started at Mon Nov 25 14:30:02 ALMT 2013
Load average for db1 is 10 which is less than 100
Load average for db2 is 3 which is less than 100
Load average for db3 is 6 which is less than 100
Load average for db4 is 5 which is less than 100
Load average for db5 is 5 which is less than 100
Mon Nov 25                                                                                 page

我试着用它：

perl -0777 -lpe 's|Started .*? page||xsg' 1

但是删除了我要打印的整个区域。

Answer 1

它可以成功：

$ awk '/^Started/ {p=1} p; /page$/ {p=0}' file
Started at Mon Nov 25 14:30:02 ALMT 2013
Load average for db1 is 10 which is less than 100
Load average for db2 is 3 which is less than 100
Load average for db3 is 6 which is less than 100
Load average for db4 is 5 which is less than 100
Load average for db5 is 5 which is less than 100
Mon Nov 25                                                                                 page

/^Started/ {p=1}当找到以“已开始”开头的字符串时，则标记p设置为1.

p

p打印该行。
/page$/ {p=0}当找到以“page”结尾的字符串时，标志p将设置为0.

此外，（thanks 1_CR）：

awk '/^Started/,/page$/' file

Answer 2

或sed。但请注意，如果遇到“开始”标记而不是“结束”，它将打印从开始标记到文件结尾的所有内容

sed -n '/^Started/, /page/p' file

Answer 3

尝试以下方法：

$ perl -0777 -lpe 's|.*(Started .*? page).*|$1|xsg' 1

Answer 4

perl -0777 -ne 'print /(Started .*? page)/xsg' 1

仅打印从开始到结束点的内容

4 个答案: