有没有更好的方法来获取wordpress中自定义帖子类型的类别名称?
<?php // get the portfolio categories
$terms = get_the_terms( $post->ID, 'filters' );
if ( $terms && ! is_wp_error( $terms ) ) :
$names = array();
$slugs = array();
foreach ( $terms as $term ) {
$names[] = $term->name;
$slugs[] = $term->slug;
}
$name_list = join( " / ", $names );
$slug_list = join( " category-", $slugs );
endif;
?>
<!-- BEGIN portfolio-item-->
<li class="portfolio-item third column category-<?php echo $slug_list; ?>" data-filter="category-<?php echo $slug_list; ?>">
答案 0 :(得分:15)
<?php
$taxonomy = 'filters';
$terms = get_terms($taxonomy);
if ( $terms && !is_wp_error( $terms ) ) :
?>
<ul>
<?php foreach ( $terms as $term ) { ?>
<li><a href="<?php echo get_term_link($term->slug, $taxonomy); ?>"><?php echo $term->name; ?></a></li>
<?php } ?>
</ul>
<?php endif;?>
或者在functions.php中输入:
function get_the_category_custompost( $id = false, $tcat = 'category' ) {
$categories = get_the_terms( $id, $tcat );
if ( ! $categories )
$categories = array();
$categories = array_values( $categories );
foreach ( array_keys( $categories ) as $key ) {
_make_cat_compat( $categories[$key] );
}
return apply_filters( 'get_the_categories', $categories );
}
并将该函数调用为:
<?php $cat = get_the_category_custompost($post->ID, 'Your Custom Taxonomy'); ?>
答案 1 :(得分:4)
我的回答似乎太简单了,但是我用它来列出一个名为DW Question Answer的wordpress插件中的类别,该插件与标准wp类别有不同的类别。
我假设Design Wall使用自定义帖子类型来创建q&amp; a part和分类以创建类别。
<ul>
<?php wp_list_categories('taxonomy=dwqa-question_category&hide_empty=0&orderby=id&title_li=');?>
</ul>
答案 2 :(得分:0)
假设您的自定义分类是recipegroups,我已经在functions.php中实现并测试了这段代码,我相信它也适用于插件。
$recipeTerms = get_terms(array(
'taxonomy' => 'recipegroups',
));
foreach($recipeTerms as $recipeTerm){
if($recipeTerm->parent==0){
echo "<div class='termsBox'>"; // remove these div's to suit your needs..
$termLink =get_term_link( $recipeTerm );
echo "<a href='$termLink'><div class='termParent'>".$recipeTerm->name."</div></a> ";
$termChilds = get_term_children($recipeTerm->term_id, 'recipegroups' );
foreach($termChilds as $child){
$chTerm = get_term_by( 'id', $child, 'recipegroups');
$termLink =get_term_link( $chTerm );
echo "<a href='$termLink'><div class='top-cat-items'>".$chTerm->name."</div></a>";
}
echo "</div>"; // end of termsBox div
}
}