Question

我的测试文件夹结构如下所示：

<test>
    <test1>
    <test2>
    <test3>

是否可以编写一个makefile，在单个文件夹或文件夹的一些列表中执行测试？

由于

Answer 1

当然有可能：

# I like to allow the user to override the default mocha with whatever
# they want in case they are running an experimental version.
MOCHA?=mocha

# Useful to pass ad hoc parameters to mocha.
MOCHA_PARAMS?=

# To work around the fact that commas are argument separators.
comma:=,

.PHONY: test test%

# Do all the tests.
test:
    $(MOCHA) --recursive $(MOCHA_PARAMS)

# Allows for combining tests in an ad hoc manner.
test%:
        $(MOCHA) $(MOCHA_PARAMS) $(foreach test,$(subst $(comma), ,$(@:test%=%)),test/test$(test))

最后一个目标允许您执行以下操作：

make test1 # runs the tests in test/test1 only
make test1,2 # runs the tests in test/test1 and test/test2
make test1,2,3 # runs the tests in test/test1, test/test2, test/test3
make test1,3 # runs the tests in test/test1, and test/test3

最后一个目标中发生的事情是目标名称（例如test1,2）已剥离test前缀，在逗号上拆分，然后每个部分都以test/test为前缀

如果要测试它，请将上面的代码复制到Makefile中，然后创建test目录和任意数量的名为test1，test2，... {{testN的子目录。 1}}在它下面。

Answer 2

根本不需要使用make。尝试将以下内容添加到package.json的脚本部分：

"test": "mocha -R spec --recursive",
"test1": "mocha -R spec test/test1",
"test2": "mocha -R spec test/test2",
"test3": "mocha -R spec test/test3",
"test13": "mocha -R spec test/test1 test/test3",

然后，您可以npm test或npm run test或npm run test13。

Answer 3

我的解决方案是

test:
  @./node_modules/.bin/mocha -R spec -r should --recursive
cloudApi:
  find $(CURDIR)/test/cloudApi -iname "*.js" | xargs node_modules/mocha/bin/mocha -R spec -r should 
injectors:
  find $(CURDIR)/test/injectors -iname "*.js" | xargs node_modules/mocha/bin/mocha -R spec -r should  

.PHONY: test cloudApi injectors

并且执行本身看起来像： mocha test / cloudApi / injectors ...

如何使用makefile和mocha在子文件夹中运行测试

3 个答案: