Question

给出以下情况：

我在tiles.xml中定义了我的JSP视图
我的所有JSP文件都位于WEB-INF / pages下，并有自己的子文件夹

我如何定义我的viewResolver，Spring控制器通过Apache Tiles定义名称查找视图？

示例：

<definition name="loginForm" extends="baseLayout">
- ＆GT;将会由new ModelAndView("loginForm");

的ViewResolver

@Configuration
@EnableWebMvc
@ComponentScan("com.itensis.holidayplanner")
public class WebAppConfig extends WebMvcConfigurerAdapter {

    @Bean
    public UrlBasedViewResolver setupViewResolver() {
        UrlBasedViewResolver resolver = new UrlBasedViewResolver();
        resolver.setPrefix("/WEB-INF/pages/");
        resolver.setSuffix(".jsp");
        resolver.setViewClass(JstlView.class);
        return resolver;
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/webjars/**").addResourceLocations("/webjars/");
        registry.addResourceHandler("/css/**").addResourceLocations("/css/");
        registry.addResourceHandler("/img/**").addResourceLocations("/img/");
    }

    @Bean
    public UrlBasedViewResolver viewResolver() {
        UrlBasedViewResolver viewResolver = new UrlBasedViewResolver();
        viewResolver.setViewClass(TilesView.class);
        return viewResolver;
    }

    @Bean
    public TilesConfigurer tilesConfigurer() {
        TilesConfigurer tilesConfigurer = new TilesConfigurer();
        tilesConfigurer.setDefinitions(new String[] { "/WEB-INF/tiles.xml" });
        tilesConfigurer.setCheckRefresh(true);
        return tilesConfigurer;
    }
}

的LoginController：

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class LoginController {

    @RequestMapping(value={"/login"}, method=RequestMethod.GET)
    public ModelAndView showLoginPage() {
        return new ModelAndView("loginForm");
    }

    @RequestMapping(value="/success-login", method=RequestMethod.GET)  
    public ModelAndView successLogin() {  
        return new ModelAndView("dashboardForm");  
    } 

    @RequestMapping(value="/error-login", method=RequestMethod.GET)  
    public ModelAndView invalidLogin() {  
        ModelAndView modelAndView = new ModelAndView("loginForm");  
        modelAndView.addObject("error", true);  
        return modelAndView;  
    }  

    @RequestMapping(value="/logout", method=RequestMethod.POST)  
    public ModelAndView logout() {  
        return new ModelAndView("loginForm");
    }  
}

Apache Tiles defintion（tiles.xml）：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE tiles-definitions PUBLIC "-//Apache Software Foundation//DTD Tiles Configuration 3.0//EN" "http://tiles.apache.org/dtds/tiles-config_3_0.dtd">

<tiles-definitions>
    <definition name="baseLayout" template="/WEB-INF/pages/template/layout.jsp">
        <put-attribute name="title" value="Holiday Planner" />
        <put-attribute name="header" value="/WEB-INF/pages/template/header.jsp" />
        <put-attribute name="navigation" value="/WEB-INF/pages/template/navigation.jsp" />
        <put-attribute name="content" value="" />
        <put-attribute name="footer" value="/WEB-INF/pages/template/footer.jsp" />
        <put-attribute name="include" value="/WEB-INF/pages/template/include.jsp" />
    </definition>

    <definition name="loginForm" extends="baseLayout">
        <put-attribute name="navigation" value="" />
        <put-attribute name="content" value="/WEB-INF/pages/login/login.jsp" />
        <put-attribute name="footer" value="" />
    </definition>

    <definition name="dashboardForm" extends="baseLayout">
        <put-attribute name="content" value="/WEB-INF/pages/dashboard/dashboard.jsp" />
    </definition>

</tiles-definitions>

Answer 1

我认为这不是完整的答案。是的，你不能有两个这样的定义，但是你可以设置解析器的顺序。

viewResolver.setOrder(1);

Answer 2

我可以看到您有ViewResolver的两个定义：setupViewResolver()中的一个和viewResolver()中的另一个定义。你应该删除第一个并离开第二个。

如何使用Spring Controller解析Apache Tiles定义

2 个答案: