我有以下两种方法将图像上传到远程servlet。由于某种原因,第二个参数是arraybuffer没有写入post请求,我试图弄清楚为什么会发生这种情况。有人可以帮助我。
setupBinaryMessage = function(metadata) {
log(metadata);
var msglen = metadata.length;
var localcanvas =document.getElementById("image");
var fullBuffer;
var myArray;
if(localcanvas){
var localcontext = localcanvas.getContext('2d');
//FOLLOWING 2 LINE OF CODE CONVERTS THE IMAGEDATA TO BINARY
var imagedata = localcontext.getImageData(0, 0, localcanvas.width, localcanvas.height);
var canvaspixelarray = imagedata.data;
var canvaspixellen = canvaspixelarray.length;
var msghead= msglen+"";
var fbuflen = msglen +canvaspixellen+msghead.length;
myArray = new ArrayBuffer(fbuflen);
fullBuffer = new Uint8Array(myArray);
for (var i=0; i< msghead.length; i++) {
fullBuffer[i] = msghead.charCodeAt(i);
}
for (var i=msglen+msghead.length;i<fbuflen;i++) {
fullBuffer[i] = canvaspixelarray[count];
count++;
};
return myArray;
} else
return null;
};
upladlImageWithPost= function() {
var message =JSON.stringify(this.data);
var fullBuffer = this.setupBinaryMessage(message);
var formdata = {command : "post", imagedata : fullBuffer,};
alert(jQuery.isPlainObject( formdata ));
var imgPostRequest = $.post( "http://localhost:8080/RestClient/RestClientPOST",fullBuffer, function(response) {
response = response.trim();
console.log(response);
if(response == "SERVER_READY"){
alert(response);
try {
}catch (error) {
alert("Web Socket Error "+error.message);
}
} else {
alert("SERVER ERROR");
}
}.bind(this))
答案 0 :(得分:0)
好的,在GURU的帮助下,我想出了这个问题。显然ARRAYBUFFER已经过时,真正的解决方案就是发布unisinged缓冲区。但即便如此,我需要将AJAX响应类型设置为ARRAYBUFFER,然后不使用JQuery $ .post但是 使用原始的纯XHTTPRequest。