Question

使用时

request.environ['QUERY_STRING']

我正在获得价值ugq_no=2，但我怎样才能获得 2 的价值？

参考代码：

def get_ugall_record(request):           
    qry_obj = db.Query(user_guide).order('ugq_no')             
    all_list = []    
    for q in qry_obj: 
        all_list.append(q)  
    return HttpResponse(serializers.serialize('json', all_list), mimetype='application/json')

def get_faqall_record(request):        
    qry_obj = db.Query(faqs).order('faq_no')             
    all_list = []    
    for q in qry_obj: 
        all_list.append(q)  
    return HttpResponse(serializers.serialize('json', all_list), mimetype='application/json')

我想在一个函数中创建这两个函数。

所以我正在尝试：

def get_ugall_record(request): 
    logging.debug('----1-----')
    logging.debug(request.GET.get('ugq_no'))
    if request.GET.get('ugq_no') != 'None':
        logging.debug('----2-----')
        ug_qry_obj = db.Query(user_guide).order('ugq_no')             
        ug_all_list = []    
        for q in ug_qry_obj: 
            ug_all_list.append(q)  
        return HttpResponse(serializers.serialize('json', ug_all_list), mimetype='application/json')
    elif request.GET.get('faq_no') != 'None':  
        logging.debug('----3-----')
        qry_obj = db.Query(faqs).order('faq_no')             
        all_list = []    
        for q in qry_obj: 
            all_list.append(q)  
        return HttpResponse(serializers.serialize('json', all_list), mimetype='application/json')

但这不是elif request.GET.get（'faq_no'）！='无' 可以做些什么？

Answer 1

使用urlparse.parse_qs：

>>> import urlparse
>>> formdata = urlparse.parse_qs('ugq_no=2')
>>> formdata
{'ugq_no': ['2']}
>>> formdata['ugq_no']
['2']
>>> formdata['ugq_no'][0]
'2'

在Python 3.x中，使用urllib.parse.parse_qs：

>>> import urllib.parse
>>> formdata = urllib.parse.parse_qs('ugq_no=2')
>>> formdata
{'ugq_no': ['2']}
>>> formdata['ugq_no']
['2']
>>> formdata['ugq_no'][0]
'2'

或使用request.GET：

value = request.GET.get('ugq_no')

<强>更新

def get_ugall_record(request): 
    if 'ugq_no' in request.GET:
        qry_obj = db.Query(user_guide).order('ugq_no')             
        return qry_response(qry_obj)
    elif 'faq_no' in request.GET:
        qry_obj = db.Query(faqs).order('faq_no')             
        return qry_response(qry_obj)

def qry_response(qry_obj):
    all_list = []
    for q in qry_obj:
        all_list.append(q)
    return HttpResponse(serializers.serialize('json', all_list), mimetype='application/json')

如何在python中获取request.environ值？

1 个答案: