根据文化寻找周末

时间:2010-01-07 08:35:53

标签: .net datetime cultureinfo

有没有办法根据使用.NET框架的不同文化找到构成周末或工作周的日子?例如,一些穆斯林国家从周日到周四有一个工作周。

5 个答案:

答案 0 :(得分:3)

我唯一知道的是如何让这一周开始。也许这有助于:

CultureInfo.CurrentCulture.DateTimeFormat.FirstDayOfWeek
来自System.Globalization

,也许你会在这个包里找到一些东西。

有几个日历类,如JulianCalendar, HebrewCalendar等。有可能找到你想要的东西。

答案 1 :(得分:3)

没有人有解决方案,所以我写了一个。这使用国家来确定一天是工作日,周末还是1/2工作日(某些国家/地区的星期六)。这方面有些含糊不清,因为墨西哥星期六的半天是“习惯性的”,但不是正式的。对于这样的情况,我将其设置为工作时间。

这包括除马来西亚其他3个省份以外的所有省份,这些省份与马来西亚其他省份不同。 AFAIK,CultureInfo.Name对这3个省没有明显的价值。最有趣的国家,文莱周末是周五和周四星期天,星期六是工作日。

代码可以Is it the weekend下载为项目吗?主要代码如下:

using System;
using System.Globalization;

namespace windward
{
    /// <summary>
    /// Extensions for the CultureInfo class.
    /// </summary>
    public static class CultureInfoExtensions
    {
        /// <summary>
        /// The weekday/weekend state for a given day.
        /// </summary>
        public enum WeekdayState
        {
            /// <summary>
            /// A work day.
            /// </summary>
            Workday,
            /// <summary>
            /// A weekend.
            /// </summary>
            Weekend,
            /// <summary>
            /// Morning is a workday, afternoon is the start of the weekend.
            /// </summary>
            WorkdayMorning
        }

        /// <summary>
        /// Returns the English version of the country name. Extracted from the CultureInfo.EnglishName.
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <returns>The English version of the country name.</returns>
        public static string GetCountryEnglishName(this CultureInfo ci)
        {
            string[] parts = ci.EnglishName.Split(new[] {'(', ')'}, StringSplitOptions.RemoveEmptyEntries);
            if (parts.Length < 2)
                return ci.EnglishName;
            parts = parts[1].Split(new[] {','}, StringSplitOptions.RemoveEmptyEntries);
            return parts[parts.Length - 1].Trim();
        }

        /// <summary>
        /// Returns the English version of the language name. Extracted from the CultureInfo.EnglishName.
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <returns>The English version of the language name.</returns>
        public static string GetLanguageEnglishName(this CultureInfo ci)
        {
            string[] parts = ci.EnglishName.Split(new[] {'('}, StringSplitOptions.RemoveEmptyEntries);
            return parts[0].Trim();
        }

        /// <summary>
        /// Return if the passed in day of the week is a weekend.
        /// 
        /// note: state pulled from http://en.wikipedia.org/wiki/Workweek_and_weekend
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <param name="day">The Day of the week to return the stat of.</param>
        /// <returns>The weekday/weekend state of the passed in day of the week.</returns>
        public static WeekdayState IsWeekend(this CultureInfo ci, DayOfWeek day)
        {
            string[] items = ci.Name.Split(new[] {'-'}, StringSplitOptions.RemoveEmptyEntries);
            switch (items[items.Length - 1])
            {
                case "DZ": // Algeria
                case "BH": // Bahrain
                case "BD": // Bangladesh
                case "EG": // Egypt
                case "IQ": // Iraq
                case "IL": // Israel
                case "JO": // Jordan
                case "KW": // Kuwait
                case "LY": // Libya
                // Northern Malaysia (only in the states of Kelantan, Terengganu, and Kedah)
                case "MV": // Maldives
                case "MR": // Mauritania
                case "NP": // Nepal
                case "OM": // Oman
                case "QA": // Qatar
                case "SA": // Saudi Arabia
                case "SD": // Sudan
                case "SY": // Syria
                case "AE": // U.A.E.
                case "YE": // Yemen
                    return day == DayOfWeek.Thursday || day == DayOfWeek.Friday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

                case "AF": // Afghanistan
                case "IR": // Iran
                    if (day == DayOfWeek.Thursday)
                        return WeekdayState.WorkdayMorning;
                    return day == DayOfWeek.Friday ? WeekdayState.Weekend : WeekdayState.Workday;

                case "BN": // Brunei Darussalam
                    return day == DayOfWeek.Friday || day == DayOfWeek.Sunday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

                case "MX": // Mexico
                case "TH": // Thailand
                    if (day == DayOfWeek.Saturday)
                        return WeekdayState.WorkdayMorning;
                    return day == DayOfWeek.Saturday || day == DayOfWeek.Sunday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

            }

            // most common Saturday/Sunday
            return day == DayOfWeek.Saturday || day == DayOfWeek.Sunday ? WeekdayState.Weekend : WeekdayState.Workday;
        }
    }
}

答案 2 :(得分:0)

我不会给你一个.NET答案,但我会说你不会以“文化”为基础,而是以国家为基础。

您可以从知识产权中获得国家的准确度(但绝不会是100%)。在那之后,我会建议大量的谷歌搜索,因为我怀疑你会找到已经编写的代码。

(您也可以查看一些开源日历/约会程序,尤其是广泛使用的程序,如Linux,或者Lightning,Thunderbird插件。如果您浏览他们的代码,您可能会找到相关的数据此)

幸运的是,你只是面对一件事,而不是一件难以实施的事情。

祝你好运!

答案 3 :(得分:0)

发现这个问题很有意思 - 我自己没有答案..但找到了一个有趣的资源 - 还讨论了日历。

Calendar converter

答案 4 :(得分:0)

以下代码将一直有效,直到过去2天被视为文化周末。

:)

/// <summary>
/// Returns true if the specified date is weekend in given culture
/// is in. 
/// </summary>
public static bool IsItWeekend(DateTime currentDay, CultureInfo cultureInfo)
{
    bool isItWeekend = false;

    DayOfWeek firstDay = cultureInfo.DateTimeFormat.FirstDayOfWeek;

    DayOfWeek currentDayInProvidedDatetime = currentDay.DayOfWeek;

    DayOfWeek lastDayOfWeek = firstDay + 4;

    if (currentDayInProvidedDatetime == lastDayOfWeek + 1 || currentDayInProvidedDatetime == lastDayOfWeek + 2)
        isItWeekend = true;

    return isItWeekend;         
}

Amit Tonk