package functiontest;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
public class FunctionTest {
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
int option=0;
System.out.println("Please enter your position:");
System.out.println("\n\t1.\tAdministrator");
System.out.println("\t2.\tManagement");
System.out.println("\t3.\tClerk");
System.out.println("\t4.\tEngineer");
System.out.println("\t5.\tExit system");
System.out.print("\n\tYour position:\t");
do
{
option = scan.nextInt();
if(option<1 || option > 5) System.out.print("You have enter wrong position" +
"\nPlease choose your position again[1...5]:\t");
}while(option<1 || option > 5);
switch(option)
{
case 1:administrator();break;
case 2:System.exit(0);break;
}
}
public static void administrator()
{
Scanner ascan = new Scanner(System.in);
String username="administrator";
String password="password";
String iusername, ipassword;
do{
System.out.print("Please enter username:\t");
iusername = ascan.nextLine();
System.out.println("Your username:\t" + iusername);
System.out.print("Please enter password:\t");
ipassword = ascan.nextLine();
System.out.println("The password you enter:\t" + ipassword);
if(iusername.equalsIgnoreCase(username) && ipassword.equalsIgnoreCase(password))
{
System.out.println("you have enter wrong username or password");
System.out.println("The system will exit");
System.exit(0);
}
}while(iusername.equalsIgnoreCase(username) && ipassword.equalsIgnoreCase(password));
int option;
System.out.println("Login successful!");
System.out.println("1. \tadd clerk");
System.out.println("2. \tdelete clerk");
System.out.println("3. \tadd engineer");
System.out.println("4. \tdelete engineer");
option = ascan.nextInt();ascan.nextLine();
}
}
首先我指定了我的用户名和密码:
String username="administrator";
String password="password";
从
中的用户密钥中读取用户名和密码iusername = ascan.nextLine();
ipassword = ascan.nextLine();
最后在密码和用户名之间进行比较:
iusername.equalsIgnoreCase(username) && ipassword.equalsIgnoreCase(password)
这是我运行程序后的结果:
run:
Please enter your position:
1. Administrator
2. Management
3. Clerk
4. Engineer
5. Exit system
Your position: 1
Please enter username: administrator
Your username: administrator
Please enter password: password
The password you enter: password
you have enter wrong username or password
The system will exit
BUILD SUCCESSFUL (total time: 22 seconds)
当我比较用户名和密码时,它总是说不匹配,在我尝试打印用户名和密码后,我确定我是正确的, 但程序总是说我输入了错误的用户名和密码,我可能知道我做错了吗?
答案 0 :(得分:3)
看看你的代码。您已经说过“如果用户名和密码正确,请打印一条消息说他们错了,然后退出。”
答案 1 :(得分:2)
而不是
if(iusername.equalsIgnoreCase(username) && ipassword.equalsIgnoreCase(password))
你想要
if(!iusername.equalsIgnoreCase(username) || !ipassword.equalsIgnoreCase(password))
如果用户名或密码不正确,您的目标是打印错误消息,如果两者都不正确,则打印错误消息。
答案 2 :(得分:1)
在第一次迭代中退出循环。比较工作正常,但是你告诉程序打印错误信息,即使它是正确的。
if(iusername.equalsIgnoreCase(username) && ipassword.equalsIgnoreCase(password))
{
System.out.println("you have enter wrong username or password");
System.out.println("The system will exit");
System.exit(0);
}
你可能想要
if(!iusername.equalsIgnoreCase(username) || !ipassword.equalsIgnoreCase(password))
添加!
s
修改
您对循环的使用是POINTLESS。如果你不打算循环,那么只需取出循环部分。如果系统退出输入错误,循环的目的是什么?
如果您不希望它在有效输入上循环并在无效输入时退出,那么您需要这样做 System.out.print("Please enter username:\t");
iusername = ascan.nextLine();
System.out.println("Your username:\t" + iusername);
System.out.print("Please enter password:\t");
ipassword = ascan.nextLine();
System.out.println("The password you enter:\t" + ipassword);
if(!iusername.equalsIgnoreCase(username) || !ipassword.equalsIgnoreCase(password))
{
System.out.println("you have enter wrong username or password");
System.out.println("The system will exit");
System.exit(0);
}
忘记循环!