Question

这段代码对我来说似乎完全没问题（CS101），但我的IDE会抛出错误＆＃34;此方法必须返回boolean类型的结果＆＃34;

我不想要任何有关如何简化我的代码的提示，或者只是想要解决原因的原因/解决方案

public static boolean validation(String correct1, String correct2)
{
   Scanner in = new Scanner(System.in);

    boolean correctInput = false;
    String userInput;

    while (correctInput == false)
    {
        System.out.print("Type in " + correct1 + " or " + correct2);
        userInput = in.next();

        if ( userInput.equals(correct1) )
        {
            return true;
        }else if ( userInput.equals(correct2) )
        {
            return false;
        }else
        {
            System.out.println("Try again!");
        }
    }   
}

问题现已解决，任何人都有兴趣为什么我需要以下完整代码：

import java.util.*;
public class CheckingInput
{
public static void main(String args[])
{
    System.out.println("What is 1+1?");
    boolean answer = validation("two", "three");
    if(answer == true)
    {
        System.out.print("Correct!");
    }else if(answer == false)
    {
        System.out.print("Wrong!");
    }
}

public static boolean validation(String correct1, String correct2)
{
    Scanner in = new Scanner(System.in);
    boolean correctInput = false;
    String userInput;

    while (correctInput == false)
    {
        System.out.print("Type in " + correct1 + " or " + correct2 + ": ");
        userInput = in.next();

        if ( userInput.equals(correct1) )
        {
            correctInput = true;
            return true;

        }else if (userInput.equals(correct2))
        {
            correctInput = true;
            return false;
        }else
        {
            System.out.println("Try again!");
            correctInput = false;
        }
    }   
    return false;// Doesn't really matter, loop will never reach here
}

Answer 1

我假设无限循环是故意的，因为您正在等待用户的回复，请尝试以下操作：

public static boolean validation(String correct1, String correct2)
{
    Scanner in = new Scanner(System.in);
    String userInput;

    while (true)
    {
        System.out.print("Type in " + correct1 + " or " + correct2);
        userInput = in.next();

        if ( userInput.equals(correct1) )
        {
            return true;
        }
        else if ( userInput.equals(correct2) )
        {
            return false;
        }
        else
        {
            System.out.println("Try again!");
        }
    }

    return false; // Doesn't really matter, loop will never reach here
}

Answer 2

在循环退出的情况下，函数结束前缺少return true;或return false语句。

正确的代码不会编译？

2 个答案: