Question

我收到错误：当我运行以下语句时，无法在源表中获得稳定的行集。

   merge into table_1 c
    using (select rep_nbr, T_nbr, SF from table_2) b
    on (c.rep_id=b.rep_nbr)
    when matched then
    update set 
    c.T_ID =b.T_nbr,
    c.SF=b.SF
    when not matched then
    insert(T_id, SF)
    values(null, null);

当我在rep_nbr

之前放置时

merge into table_1 c
    using (select distinct rep_nbr,t_nbr,SF from table_2) b
    on (c.rep_id=b.rep_nbr)
    when matched then
    update set 
    c.T_ID =b.T_nbr,
    c.SF=b.SF
    when not matched then
    insert(T_id, SF)
    values(null, null);

ORA-01400：无法在c.rep_id中插入NULL。我不想填充c.rep_id，我只需要它们匹配然后更新那些匹配的记录。

Answer 1

如果我理解正确，你不需要MERGE，只需要更新。这样的事情应该有效：

UPDATE table_1 t1 
SET t1.t_id = (SELECT DISTINCT t2.t_nbr FROM table_2 t2 WHERE t1.rep_id = t2.rep_nbr),
    t1.sf = (SELECT DISTINCT t2.sf FROM table_2 t2 WHERE t1.rep_id = t2.rep_nbr),
WHERE t1.rep_id IN (SELECT rep_nbr FROM table_2)

但是，但是，在Oracle的后续版本（从10日或11日）中，您可以取出合并的部分内容，例如，取出WHEN NOT MATCHED部分。

Answer 2

删除部分“与当时不匹配”

merge into table_1 c
    using (select distinct rep_nbr,t_nbr,SF from table_2) b
    on (c.rep_id=b.rep_nbr)
    when matched then
    update set 
    c.T_ID =b.T_nbr,
    c.SF=b.SF

错误：ORA-30926：无法在源表中获取稳定的行集

2 个答案: