Question

我有一个＆＃34; edittext＆＃34;在我的应用程序中，我想在软键盘上按下某些字符时执行操作。我已尝试过各种方式以及stackOverflow的建议方式，但不会检测到a / A，b / B等字符。但是输入和Del。阅读加载后，显然我必须覆盖edittext类，根据这里的一个例子，所以我已经做到了。我在这里重写方法：

    @Override
    public boolean sendKeyEvent(KeyEvent event) {
        if (event.getAction() == KeyEvent.ACTION_DOWN
                && event.getKeyCode() == KeyEvent.KEYCODE_A) {
            ZanyEditText.this.setRandomBackgroundColor();

            return false;
        }
        return super.sendKeyEvent(event);
    }

我也试过覆盖标准的edittext onKeyListener：

txtSMS.setOnKeyListener(new View.OnKeyListener() {
            @Override
            public boolean onKey(View v, int keyCode, KeyEvent event) {
                // You can identify which key pressed buy checking keyCode value
                // with KeyEvent.KEYCODE_
                if (keyCode == KeyEvent.KEYCODE_DEL) {
                    // this is for backspace
                    Toast.makeText(getApplicationContext(), "Del was pressed", Toast.LENGTH_SHORT).show();
                }
                if (keyCode == KeyEvent.KEYCODE_A) {
                    // this is for backspace
                    Toast.makeText(getApplicationContext(), "A was pressed", Toast.LENGTH_SHORT).show();
                }
                return false;
            }

然而，在这两种情况下，Del都被检测到了。为什么我不能检测字母表中的字符？它们出现在文本框中......

由于

Answer 1

我有类似的问题，你需要使用TextWatcher，然后检测输入的最后一个字符是什么（使用＆＃39; subSequence＆＃39;）。按下了确定删除的使用逻辑或输入了a，希望这有帮助

见下面的代码：

editText.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence s, int start, int before,
                int count) {
            // TODO Auto-generated method stub
            //this is the method that detects the last entry below
            String c = s.subSequence(before, before + 1).toString();
            //check for delete
            if (before < s.length()) {
                String c = s.subSequence(before, before + 1).toString();
                //see if a was entererd
                if (c == a) {
                     //a entered

                }
            } else {
                //delete pressed

            }

        }

        @Override
        public void afterTextChanged(Editable s) {
            // TODO Auto-generated method stub

        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
            // TODO Auto-generated method stub

        }

    });

未检测到Android软键盘字母

1 个答案: