刚刚遇到一个代码,用于将力传感器的模拟读数转换为以牛顿为单位的力。我不确定它是如何完成的。希望有人可以向我解释。谢谢!我在这里找到了代码http://learn.adafruit.com/force-sensitive-resistor-fsr/using-an-fsr
if (fsrVoltage == 0) {
Serial.println("No pressure");
} else {
// The voltage = Vcc * R / (R + FSR) where R = 10K and Vcc = 5V
// so FSR = ((Vcc - V) * R) / V yay math!
fsrResistance = 5000 - fsrVoltage; // fsrVoltage is in millivolts so 5V = 5000mV
fsrResistance *= 10000; // 10K resistor
fsrResistance /= fsrVoltage;
Serial.print("FSR resistance in ohms = ");
Serial.println(fsrResistance);
fsrConductance = 1000000; // we measure in micromhos so
fsrConductance /= fsrResistance;
Serial.print("Conductance in microMhos: ");
Serial.println(fsrConductance);
// Use the two FSR guide graphs to approximate the force
if (fsrConductance <= 1000) {
fsrForce = fsrConductance / 80;
Serial.print("Force in Newtons: ");
Serial.println(fsrForce);
} else {
fsrForce = fsrConductance - 1000;
fsrForce /= 30;
Serial.print("Force in Newtons: ");
Serial.println(fsrForce);
}
}
答案 0 :(得分:0)
如果你看一下这篇文章的第6页http://www.imagesco.com/sensors/fsr/fsrguide.pdf 有两个图表,一个用于重量级,一个用于较轻的一个。如果对它们运行线性回归并转换单位,则应在代码中得到两个方程式。