Question

我目前正在停电，而且我是c ++和CORBA的新手。我试图分配一个CORBA :: Char，但我得到一个Compiler-Error“错误：从'CORBA :: Char *'无效转换为'CORBA：Char'。有没有人有想法，我的代码有什么问题以及如何写得对吗？

谢谢！西蒙

class Medium_impl : virtual public POA_Media::Medium {
public:
    CORBA::Char gettype();
    void settype(CORBA::Char);

private:
    CORBA::Char type;                                   
};

Medium_impl::Medium_impl (char* _oidstr) {
    type='V';
}

void Medium_impl::settype(CORBA::Char _type){
    type = _type;
}

CORBA::Char Medium_impl::gettype(){
    return type;
}

我在测试中得到错误 - Methode aref - ＆gt; settype（type [i]）;

void Mediathek_impl::test (void) {

CORBA::Char type[10][1];

strcpy(type[0],"V");

for(int i = 0; i<=9;i++){
    char oidstr[20];

    sprintf(oidstr,"medium_%d.acc",count);
    PortableServer::ObjectId_var     tmpoid=PortableServer::string_to_ObjectId(oidstr);

    CORBA::Object_var obj = mypoa->create_reference_with_id (tmpoid,"IDL:Medium:1.0");
    ::Media::Medium_ptr aref = ::Media::Medium::_narrow (obj);
    assert (!CORBA::is_nil (aref));
    oid[count] = mypoa->reference_to_id(aref);

    //here I get the Compiler-error
    aref ->settype(type[i]);    

    count ++; 
}

Answer 1

type已声明为：

CORBA::Char type[10][1];

然后，type[i]为CORBA::Char*，构建者抱怨不知道如何将其转换为CORBA::Char。我想你想要：

aref ->settype(type[i][0]);

或

CORBA::Char type[10];

strcpy(type,"V");

从CORBA :: Char *到CORBA :: Char的无效转换

1 个答案: