我正在尝试做一些我认为相对简单的事情：使用Android SDK将图像上传到服务器。我找到了很多示例代码：
http://linklens.blogspot.com/2009/06/android-multipart-upload.html
但是对我来说都不起作用。我一直遇到的困惑是制作多部分请求真正需要的东西。 Android的多部分上传（带图片）的最简单方法是什么？
非常感谢任何帮助或建议！
答案 0 :(得分：102)
2014年4月29日更新：
我的回答现在有点老了，我想你更想使用某种高级库，例如Retrofit。
基于此博客，我提出了以下解决方案： http://blog.tacticalnuclearstrike.com/2010/01/using-multipartentity-in-android-applications/
您必须下载其他库才能MultipartEntity正在运行！
1）从http://james.apache.org/download.cgi#Apache_Mime4J下载httpcomponents-client-4.1.zip并将apache-mime4j-0.6.1.jar添加到您的项目中。
2）从http://hc.apache.org/downloads.cgi下载httpcomponents-client-4.1-bin.zip，并将httpclient-4.1.jar，httpcore-4.1.jar和httpmime-4.1.jar添加到您的项目中。
3）使用下面的示例代码。
private DefaultHttpClient mHttpClient;
public ServerCommunication() {
HttpParams params = new BasicHttpParams();
params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);
mHttpClient = new DefaultHttpClient(params);
}
public void uploadUserPhoto(File image) {
try {
HttpPost httppost = new HttpPost("some url");
MultipartEntity multipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
multipartEntity.addPart("Title", new StringBody("Title"));
multipartEntity.addPart("Nick", new StringBody("Nick"));
multipartEntity.addPart("Email", new StringBody("Email"));
multipartEntity.addPart("Description", new StringBody(Settings.SHARE.TEXT));
multipartEntity.addPart("Image", new FileBody(image));
httppost.setEntity(multipartEntity);
mHttpClient.execute(httppost, new PhotoUploadResponseHandler());
} catch (Exception e) {
Log.e(ServerCommunication.class.getName(), e.getLocalizedMessage(), e);
}
}
private class PhotoUploadResponseHandler implements ResponseHandler<Object> {
@Override
public Object handleResponse(HttpResponse response)
throws ClientProtocolException, IOException {
HttpEntity r_entity = response.getEntity();
String responseString = EntityUtils.toString(r_entity);
Log.d("UPLOAD", responseString);
return null;
}
}
答案 1 :(得分：46)
由于MultiPartEntity 已弃用 。所以这是新方法！而且您只需要httpcore.jar(latest)和httpmime.jar(latest)从Apache站点下载它们。
try
{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(URL);
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
entityBuilder.addTextBody(USER_ID, userId);
entityBuilder.addTextBody(NAME, name);
entityBuilder.addTextBody(TYPE, type);
entityBuilder.addTextBody(COMMENT, comment);
entityBuilder.addTextBody(LATITUDE, String.valueOf(User.Latitude));
entityBuilder.addTextBody(LONGITUDE, String.valueOf(User.Longitude));
if(file != null)
{
entityBuilder.addBinaryBody(IMAGE, file);
}
HttpEntity entity = entityBuilder.build();
post.setEntity(entity);
HttpResponse response = client.execute(post);
HttpEntity httpEntity = response.getEntity();
result = EntityUtils.toString(httpEntity);
Log.v("result", result);
}
catch(Exception e)
{
e.printStackTrace();
}
答案 2 :(得分：13)
这是LIGHT WEIGHTED解决方案，对我来说没有外部HTTPCore和这样的libs。我正面临着64K方法的问题，所以没有任何选择可以避免使用HTTPCore库
import java.util.List;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import java.util.ArrayList;
import java.util.List;
/**
* This utility class provides an abstraction layer for sending multipart HTTP
* POST requests to a web server.
*
* @author www.codejava.net
*/
public class MultipartUtility {
private final String boundary;
private static final String LINE_FEED = "\r\n";
private HttpURLConnection httpConn;
private String charset;
private OutputStream outputStream;
private PrintWriter writer;
/**
* This constructor initializes a new HTTP POST request with content type
* is set to multipart/form-data
*
* @param requestURL
* @param charset
* @throws IOException
*/
public MultipartUtility(String requestURL, String charset)
throws IOException {
this.charset = charset;
// creates a unique boundary based on time stamp
boundary = "===" + System.currentTimeMillis() + "===";
URL url = new URL(requestURL);
httpConn = (HttpURLConnection) url.openConnection();
httpConn.setUseCaches(false);
httpConn.setDoOutput(true); // indicates POST method
httpConn.setDoInput(true);
httpConn.setRequestProperty("Content-Type",
"multipart/form-data; boundary=" + boundary);
httpConn.setRequestProperty("User-Agent", "CodeJava Agent");
httpConn.setRequestProperty("Test", "Bonjour");
outputStream = httpConn.getOutputStream();
writer = new PrintWriter(new OutputStreamWriter(outputStream, charset),
true);
}
/**
* Adds a form field to the request
*
* @param name field name
* @param value field value
*/
public void addFormField(String name, String value) {
writer.append("--" + boundary).append(LINE_FEED);
writer.append("Content-Disposition: form-data; name=\"" + name + "\"")
.append(LINE_FEED);
writer.append("Content-Type: text/plain; charset=" + charset).append(
LINE_FEED);
writer.append(LINE_FEED);
writer.append(value).append(LINE_FEED);
writer.flush();
}
/**
* Adds a upload file section to the request
*
* @param fieldName name attribute in <input type="file" name="..." />
* @param uploadFile a File to be uploaded
* @throws IOException
*/
public void addFilePart(String fieldName, File uploadFile)
throws IOException {
String fileName = uploadFile.getName();
writer.append("--" + boundary).append(LINE_FEED);
writer.append(
"Content-Disposition: form-data; name=\"" + fieldName
+ "\"; filename=\"" + fileName + "\"")
.append(LINE_FEED);
writer.append(
"Content-Type: "
+ URLConnection.guessContentTypeFromName(fileName))
.append(LINE_FEED);
writer.append("Content-Transfer-Encoding: binary").append(LINE_FEED);
writer.append(LINE_FEED);
writer.flush();
FileInputStream inputStream = new FileInputStream(uploadFile);
byte[] buffer = new byte[4096];
int bytesRead = -1;
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
outputStream.flush();
inputStream.close();
writer.append(LINE_FEED);
writer.flush();
}
/**
* Adds a header field to the request.
*
* @param name - name of the header field
* @param value - value of the header field
*/
public void addHeaderField(String name, String value) {
writer.append(name + ": " + value).append(LINE_FEED);
writer.flush();
}
/**
* Completes the request and receives response from the server.
*
* @return a list of Strings as response in case the server returned
* status OK, otherwise an exception is thrown.
* @throws IOException
*/
public List<String> finish() throws IOException {
List<String> response = new ArrayList<String>();
writer.append(LINE_FEED).flush();
writer.append("--" + boundary + "--").append(LINE_FEED);
writer.close();
// checks server's status code first
int status = httpConn.getResponseCode();
if (status == HttpURLConnection.HTTP_OK) {
BufferedReader reader = new BufferedReader(new InputStreamReader(
httpConn.getInputStream()));
String line = null;
while ((line = reader.readLine()) != null) {
response.add(line);
}
reader.close();
httpConn.disconnect();
} else {
throw new IOException("Server returned non-OK status: " + status);
}
return response;
}
}
USAGE
private void uploadMedia() {
try {
String charset = "UTF-8";
File uploadFile1 = new File("/sdcard/myvideo.mp4");
String requestURL = Data.BASE_URL+Data.URL_UPLOAD_REACTION_TEST;
MultipartUtility multipart = new MultipartUtility(requestURL, charset);
// multipart.addHeaderField("User-Agent", "CodeJava");
// multipart.addHeaderField("Test-Header", "Header-Value");
multipart.addFormField("friend_id", "Cool Pictures");
multipart.addFormField("userid", "Java,upload,Spring");
multipart.addFilePart("uploadedfile", uploadFile1);
List<String> response = multipart.finish();
Log.v("rht", "SERVER REPLIED:");
for (String line : response) {
Log.v("rht", "Line : "+line);
}
} catch (Exception e) {
e.printStackTrace();
}
}
PHP代码接受上传
<?php
$friend_id = $_REQUEST['friend_id'];
$userid = $_REQUEST['userid'];
echo 'friend_id : '.$friend_id. ' userid '.$userid;
move_uploaded_file($_FILES['uploadedfile']['tmp_name'], "./uploads/".$_FILES["uploadedfile"]["name"]);
?>
答案 3 :(得分：6)
更轻松，更轻便（32k），以及更多性能：
Android异步Http客户端库：http://loopj.com/android-async-http/
实现：
How to send a “multipart/form-data” POST in Android with Volley
答案 4 :(得分：3)
试试这个：
public void SendMultipartFile() {
Log.d(TAG, "UPLOAD: SendMultipartFile");
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost( <url> );
File file = new File("/sdcard/spider.jpg");
Log.d(TAG, "UPLOAD: setting up multipart entity");
MultipartEntity mpEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
Log.d(TAG, "UPLOAD: file length = " + file.length());
Log.d(TAG, "UPLOAD: file exist = " + file.exists());
try {
mpEntity.addPart("datafile", new FileBody(file, "application/octet"));
mpEntity.addPart("id", new StringBody("1"));
} catch (UnsupportedEncodingException e1) {
Log.d(TAG, "UPLOAD: UnsupportedEncodingException");
e1.printStackTrace();
}
httppost.setEntity(mpEntity);
Log.d(TAG, "UPLOAD: executing request: " + httppost.getRequestLine());
Log.d(TAG, "UPLOAD: request: " + httppost.getEntity().getContentType().toString());
HttpResponse response;
try {
Log.d(TAG, "UPLOAD: about to execute");
response = httpclient.execute(httppost);
Log.d(TAG, "UPLOAD: executed");
HttpEntity resEntity = response.getEntity();
Log.d(TAG, "UPLOAD: respose code: " + response.getStatusLine().toString());
if (resEntity != null) {
Log.d(TAG, "UPLOAD: " + EntityUtils.toString(resEntity));
}
if (resEntity != null) {
resEntity.consumeContent();
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
答案 5 :(得分：2)
我强烈推荐Loopj。
我已成功使用它一次上传多个文件，包括不同的mime类型。只需这样做：
File myVideo = new File("/path/to/myvideo.mp4");
File myPic = new File("/path/to/mypic.jpg");
RequestParams params = new RequestParams();
try {
params.put("profile_picture", myPic);
params.put("my_video", myVideo);
} catch(FileNotFoundException e) {}
对于大文件或多文件，您可能需要增加超时量，否则使用的默认超时可能太短：
client.setTimeout(500000) //make this the appropriate timeout in milliseconds
请查看此链接以获取loopj的完整说明以及如何使用它，到目前为止我遇到的最简单的异步http库：
http://loopj.com/android-async-http/ http://loopj.com/android-async-http/doc/com/loopj/android/http/AsyncHttpClient.html
答案 6 :(得分：1)
删除所有httpclient，httpmime依赖项并添加此依赖项compile 'commons-httpclient:commons-httpclient:3.1'。此依赖项已内置MultipartRequestEntity，因此您可以轻松地将一个或多个文件上载到服务器
public class FileUploadUrlConnection extends AsyncTask<String, String, String> {
private Context context;
private String url;
private List<File> files;
public FileUploadUrlConnection(Context context, String url, List<File> files) {
this.context = context;
this.url = url;
this.files = files;
}
@Override
protected String doInBackground(String... params) {
HttpClient client = new HttpClient();
PostMethod post = new PostMethod(url);
HttpClientParams connectionParams = new HttpClientParams();
post.setRequestHeader(// Your header goes here );
try {
Part[] parts = new Part[files.size()];
for (int i=0; i<files.size(); i++) {
Part part = new FilePart(files.get(i).getName(), files.get(i));
parts[i] = part;
}
MultipartRequestEntity entity = new MultipartRequestEntity(parts, connectionParams);
post.setRequestEntity(entity);
int statusCode = client.executeMethod(post);
String response = post.getResponseBodyAsString();
Log.v("Multipart "," "+response);
if(statusCode == 200) {
return response;
}
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
您还可以添加请求和响应超时
client.getParams().setParameter(CoreConnectionPNames.CONNECTION_TIMEOUT, 10000);
client.getParams().setParameter(CoreConnectionPNames.SO_TIMEOUT, 10000);
答案 7 :(得分：0)
我可以推荐使用3种依赖的Ion库，你可以在这两个站点找到所有三个jar文件：
https://github.com/koush/ion#jars（离子和androidasync）
try {
Ion.with(this, "http://www.urlthatyouwant.com/post/page")
.setMultipartParameter("field1", "This is field number 1")
.setMultipartParameter("field2", "Field 2 is shorter")
.setMultipartFile("imagefile",
new File(Environment.getExternalStorageDirectory()+"/testfile.jpg"))
.asString()
.setCallback(new FutureCallback<String>() {
@Override
public void onCompleted(Exception e, String result) {
System.out.println(result);
}});
} catch(Exception e) {
// Do something about exceptions
System.out.println("exception: " + e);
}
这将运行异步，一旦收到响应，回调将在UI线程中执行 我强烈建议您转到https://github.com/koush/ion 进一步的信息
答案 8 :(得分：0)
如果您使用的是AOSP库Volley，这是一种简单的方法。
按如下方式扩展班级Request<T> -
public class MultipartRequest extends Request<String> {
private static final String FILE_PART_NAME = "file";
private final Response.Listener<String> mListener;
private final Map<String, File> mFilePart;
private final Map<String, String> mStringPart;
MultipartEntityBuilder entity = MultipartEntityBuilder.create();
HttpEntity httpentity;
public MultipartRequest(String url, Response.ErrorListener errorListener,
Response.Listener<String> listener, Map<String, File> file,
Map<String, String> mStringPart) {
super(Method.POST, url, errorListener);
mListener = listener;
mFilePart = file;
this.mStringPart = mStringPart;
entity.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
buildMultipartEntity();
}
public void addStringBody(String param, String value) {
mStringPart.put(param, value);
}
private void buildMultipartEntity() {
for (Map.Entry<String, File> entry : mFilePart.entrySet()) {
// entity.addPart(entry.getKey(), new FileBody(entry.getValue(), ContentType.create("image/jpeg"), entry.getKey()));
try {
entity.addBinaryBody(entry.getKey(), Utils.toByteArray(new FileInputStream(entry.getValue())), ContentType.create("image/jpeg"), entry.getKey() + ".JPG");
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
for (Map.Entry<String, String> entry : mStringPart.entrySet()) {
if (entry.getKey() != null && entry.getValue() != null) {
entity.addTextBody(entry.getKey(), entry.getValue());
}
}
}
@Override
public String getBodyContentType() {
return httpentity.getContentType().getValue();
}
@Override
public byte[] getBody() throws AuthFailureError {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
try {
httpentity = entity.build();
httpentity.writeTo(bos);
} catch (IOException e) {
VolleyLog.e("IOException writing to ByteArrayOutputStream");
}
return bos.toByteArray();
}
@Override
protected Response<String> parseNetworkResponse(NetworkResponse response) {
Log.d("Response", new String(response.data));
return Response.success(new String(response.data), getCacheEntry());
}
@Override
protected void deliverResponse(String response) {
mListener.onResponse(response);
}
}
您可以创建和添加请求，例如 -
Map<String, String> params = new HashMap<>();
params.put("name", name.getText().toString());
params.put("email", email.getText().toString());
params.put("user_id", appPreferences.getInt( Utils.PROPERTY_USER_ID, -1) + "");
params.put("password", password.getText().toString());
params.put("imageName", pictureName);
Map<String, File> files = new HashMap<>();
files.put("photo", new File(Utils.LOCAL_RESOURCE_PATH + pictureName));
MultipartRequest multipartRequest = new MultipartRequest(Utils.BASE_URL + "editprofile/" + appPreferences.getInt(Utils.PROPERTY_USER_ID, -1), new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// TODO Auto-generated method stub
Log.d("Error: ", error.toString());
FugaDialog.showErrorDialog(ProfileActivity.this);
}
}, new Response.Listener<String>() {
@Override
public void onResponse(String jsonResponse) {
JSONObject response = null;
try {
Log.d("jsonResponse: ", jsonResponse);
response = new JSONObject(jsonResponse);
} catch (JSONException e) {
e.printStackTrace();
}
try {
if (response != null && response.has("statusmessage") && response.getBoolean("statusmessage")) {
updateLocalRecord();
}
} catch (JSONException e) {
e.printStackTrace();
}
FugaDialog.dismiss();
}
}, files, params);
RequestQueue queue = Volley.newRequestQueue(this);
queue.add(multipartRequest);
答案 9 :(得分：0)
对于后人，我没有看到提到的okhttp。 Related post.
基本上，您使用MultipartBody.Builder构建正文，然后将其发布到请求中。
kotlin中的例子：
val body = MultipartBody.Builder()
.setType(MultipartBody.FORM)
.addFormDataPart(
"file",
file.getName(),
RequestBody.create(MediaType.parse("image/png"), file)
)
.addFormDataPart("timestamp", Date().time.toString())
.build()
val request = Request.Builder()
.url(url)
.post(body)
.build()
httpClient.newCall(request).enqueue(object : okhttp3.Callback {
override fun onFailure(call: Call?, e: IOException?) {
...
}
override fun onResponse(call: Call?, response: Response?) {
...
}
})
答案 10 :(得分：0)
public class Multipart{
private final Map<String, String> headrs;
private String url;
private HttpURLConnection con;
private OutputStream os;
private String delimiter = "--";
private String boundary = "TRR" + Long.toString(System.currentTimeMillis()) + "TRR";
public Multipart (String url, Map<String, String> headers) {
this.url = url;
this.headrs = headers;
}
public void connectForMultipart() throws Exception {
con = (HttpURLConnection) (new URL(url)).openConnection();
con.setRequestMethod("POST");
con.setDoInput(true);
con.setDoOutput(true);
con.setRequestProperty("Connection", "Keep-Alive");
for (Map.Entry<String, String> entry : headrs.entrySet()) {
con.setRequestProperty(entry.getKey(), entry.getValue());
}
con.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
con.connect();
os = con.getOutputStream();
}
public void addFormPart(String paramName, String value) throws Exception {
writeParamData(paramName, value);
}
public void addFilePart(String paramName, String fileName, byte[] data) throws Exception {
os.write((delimiter + boundary + "\r\n").getBytes());
os.write(("Content-Disposition: form-data; name=\"" + paramName + "\"; filename=\"" + fileName + "\"\r\n").getBytes());
os.write(("Content-Type: application/octet-stream\r\n").getBytes());
os.write(("Content-Transfer-Encoding: binary\r\n").getBytes());
os.write("\r\n".getBytes());
os.write(data);
os.write("\r\n".getBytes());
}
public void finishMultipart() throws Exception {
os.write((delimiter + boundary + delimiter + "\r\n").getBytes());
}
public String getResponse() throws Exception {
InputStream is = con.getInputStream();
byte[] b1 = new byte[1024];
StringBuffer buffer = new StringBuffer();
while (is.read(b1) != -1)
buffer.append(new String(b1));
con.disconnect();
return buffer.toString();
}
private void writeParamData(String paramName, String value) throws Exception {
os.write((delimiter + boundary + "\r\n").getBytes());
os.write("Content-Type: text/plain\r\n".getBytes());//;charset=utf-8
os.write(("Content-Disposition: form-data; name=\"" + paramName + "\"\r\n").getBytes());
;
os.write(("\r\n" + value + "\r\n").getBytes());
}
}
然后在下面打电话
Multipart multipart = new Multipart(url__, map);
multipart .connectForMultipart();
multipart .addFormPart(entry.getKey(), entry.getValue());
multipart .addFilePart(KeyName, "FileName", imagedata);
multipart .finishMultipart();
答案 11 :(得分：0)
您可以使用GentleRequest，它是用于发出http请求的轻量级库（免责声明：我是作者）：
Connections connections = new HttpConnections();
Binary binary = new PacketsBinary(new
BufferedInputStream(new FileInputStream(file)),
file.length());
//Content-Type is set to multipart/form-data; boundary=
//{generated by multipart object}
MultipartForm multipart = new HttpMultipartForm(
new HttpFormPart("user", "aplication/json",
new JSONObject().toString().getBytes()),
new HttpFormPart("java", "java.png", "image/png",
binary.content()));
Response response = connections.response(new
PostRequest(url, multipart));
if (response.hasSuccessCode()) {
byte[] raw = response.body().value();
String string = response.body().stringValue();
JSONOBject json = response.body().jsonValue();
} else {
}